Question

I'm reading through an MCAT Chemistry book and it keeps referring to HClO as a weak...

I'm reading through an MCAT Chemistry book and it keeps referring to HClO as a weak acid. I'm confused why this would be the case.

Here's my logic:
HCl is a strong acid. An electronegative atom such as oxygen should pull electron density away through induction and decrease the pKa of HCl. Therefore, wouldn't it even be an even stronger acid now?

Why am I wrong? Thank you

0 0
Add a comment Improve this question Transcribed image text
Answer #1

the dissociation of HClO happens as shown in following reaction,

HClO ---> H+ + ClO-

in ClO- ion oxygen is more electronegative element than chlorine and an electron withdrawing group too. When oxygen is attached to chlorine atom to form an anion, the negative charge on oygen gets dispersed adjacent to chlorine and hence provides stability to the anion.

As a result HClO dissociates but not as strongly as HCl does. i.e. less number of dissociations leads to less protons in solution and hence lesser acidity(weaker acid) than HCl.

Add a comment
Know the answer?
Add Answer to:
I'm reading through an MCAT Chemistry book and it keeps referring to HClO as a weak...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • General Chemistry II Part 3. Now let's consider the effect of structure on acid-base properties: There...

    General Chemistry II Part 3. Now let's consider the effect of structure on acid-base properties: There are two main factors that determine whether a molecule containing X-H bond will behave as a Bronsted-Lowry acid and donate a proton: the strength of the bond and the polarity of the bond. On one hand, the stronger the X-H bond, the lower the molecule's tendency to donate the proton. On the other hand, the more polar the X-H bond, the higher the molecules...

  • Exercise 2 Separation of a Mixture Based on Acid-Base Properties One purpose of this exercise is...

    Exercise 2 Separation of a Mixture Based on Acid-Base Properties One purpose of this exercise is to learn how to use a separatory funnel to extract a single component away from other compounds in solution. To do so, we will apply the principles of solubility and acid-base behavior you’re seeing in class. One of the compounds is neutral in the acid-base sense. It has no ability to either donate or accept a proton from an aqueous solution, and will remain...

  • For the preparation and standardization of NaOH with KHP im supposed to boil water for 1hr and 30 min to remove CO2

    For the preparation and standardization of NaOH with KHP im supposed to boil water for 1hr and 30 min to remove CO2....the problem is that if I don't boil it for that long and (30 min) b/c of not enough time but I put the water I boiled for 1/2 hr aproximately into a NaOH bottle with a CO2 absorber and stored it there for a few days. I would assume that I would have to boil the water again...but...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT