Question

Using the Ideal Gas Law (PV = nRT) and the data you gathered in your experiment, calculate the number of moles (n) of oxygen (O₂) produced in this reaction. (show your calculation) If you are not sure how to do it, please ask me questions before you submit the assignment.

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Remember to use the following units:

temperature: in kelvin (K)

volume: in liters (L)

pressure: in atmospheres (atm)

constant R = 0.0821 atm/mol x K

Data gathered from experiment:

Temp of Water: 22 degrees C

ATM: 1.003965

Initial Volume of Air: 38 mL

Final Volume of Air: 59 mL

Volume of Oxygen: 21 mL

Time Reaction Started: 6:38 pm

Time Reaction Ended: 6:39 pm

Total Reaction Time: 1 minute

Answer 1

The volume(V) of the oxygen is = 21mL = 0.021 L

Pressure(P) is given as = 1.003965 atm

Temperature(T) is given= 22^o C = (273+22) = 295 K

R = 0.082 L-atm mol^-1 K^-1

From gas law we have-

where n = number of moles

or,

or,

or,

So the number mole of oxygen = 0.00087