During Trial 1, an object is dropped from height h and requires time t to reach...
During Trial 1, an object is dropped from height h and requires time t to reach the ground. If, in Trial 2, the drop height is tripled, what will be the new time required to reach the ground in terms of t?
A. 12 t
B. 9t
C. 3t
D. √3t
The answer is D. Can someone, using the equation: x=1/2at^2 explain why the answer would be D. If x is proportional to t^2 then if x is increased by a factor of 3 wouldn't t need to be increased by a factor of 9? I am so confused.
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During Trial 1, an object is dropped from height h and requires
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