Question

Create a C++ program to :

1. Prompt user for seven test score
2. Store the scores into an array
3. Print the array before and after sorting
4. Print the test average
5. Convert the average to letter grade
6. Search for a test score 90, using linear search
   1. Print, if test score 90 was found and at what position
7. Add Comments

SEPARATE THE FILES INTO 3 : header.h, functions.cpp, main.cpp

Answer 1

The code for the above program is given below, I have commented in line for the explanation.

There are 3 separate files:-

functions.cpp

void sort(int arr[],int n) // function to sort
{
for(int i=0;i<n-1;i++) // Bubble sort
{
for(int j=i+1;j<n;j++)
{
if(arr[j]<arr[i])
{
int temp = arr[i];
arr[i] = arr[j];
arr[j] = temp;
}
}
}
}

float average(int arr[],int n) // function for average
{
float sum=0;
for(int i=0;i<n;i++)
{
sum+=arr[i];
}
  
return sum/n;
}

int search(int arr[],int n,int k) // linear search for number k
{
int temp=-1;
for(int i=0;i<n;i++)
{
if(arr[i]==k)
{
temp=i+1;
}
}
return temp;
}

header.h

// In this file we define definition fo each function
void sort(int arr[],int n);
float average(int arr[],int n);
int search(int arr[],int n,int k);

main.cpp

#include <iostream>
#include "header.h" // icluding header.h file
using namespace std;

int main()
{
int n=7;
cout<<"Enter seven Test scores: ";
int arr[n]; // defining array
  
for(int i=0;i<n;i++)
{
cin>>arr[i];
}
  
cout<<"Before sorting: \n";
for(int i=0;i<n;i++)
{
cout<<arr[i]<<" ";
}
  
sort(arr,n); // Sorting the array
cout<<"\nAfter sorting: \n";
  
for(int i=0;i<n;i++)
{
cout<<arr[i]<<" ";
}
  
float avg = average(arr,n); // calling average function
  
cout<<"\nAverage is: "<<avg<<"\n";
if(avg<=50) cout<<"Grade is C";
else if(avg<=80) cout<<"Grade is B";
else cout<<"Grade is A";
  
int srch = search(arr,n,90); // calling search function
  
if(srch!=-1)
{
cout<<"\nScore 90 was found at: "<<srch<<endl;
}
  

return 0;
}

Output

Hope it clears your doubt :)