A mixture of gases contains 0.11 mol CH4, 0.25 mol C2H6, and 0.31 mol of C3H8....
A mixture of gases contains 0.11 mol CH4, 0.25 mol C2H6, and 0.31 mol of C3H8. The total pressure is 1.50 atm. Calculate the partial pressure of CH4.
Homework Answers
Moles of CH4 = 0.11 mol
Total number of moles = 0.11 + 0.25 + 0.31 = 0.67 mol
total pressure (P) = 1.50 atm
partial pressure of CH4 = (0.11 mol / 0.67 mol) x (1.50 atm) = 0.246 atm
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