How many ways can four red balls and four blue balls be randomly placed in eight
urns that are numbered one to eight so that exactly one ball is in each urn?
This is a question of permutation.
Number of ways that 8 balls can be arranged in 8 boxes is given as 8!
We have 8 balls out of which 4 are red alike and 4 are blue alike so 8! Will be divided twice by 4! Because of repetition of alike colored balls.
Hence our required answer is 8!/(4! * 4!) = 70 ways.
How many ways can four red balls and four blue balls be randomly placed in eight...
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