Question

Python 3

Create a function that takes an array and an integer v, and returns the number of v occurrences in the array. Add a variable Nsteps to count how many times the loops have executed and display that information in a message

The main program must take an array / list 2D, call the function, and display the result.

>>>l3 = [52, 14, 14, 8, 85, 69, 1, 77, 94, 96, 51, 65, 35, 32, 87, 92, 74, 47, 27, 88, 11, 11, 26, 14, 100, 37, 62, 3, 63, 5, 20, 53, 28, 10, 43, 16, 94, 6, 82, 49, 74, 55, 89, 97, 12, 38, 72, 94, 3, 77, 42, 26, 25, 16, 89, 10, 8, 63, 93, 77, 68, 56, 74, 46, 54, 50, 80, 33, 69, 95, 2, 79, 73, 6, 31, 41, 38, 81, 88, 12, 39, 77, 49, 30, 18, 22, 40, 40, 12, 51, 69, 32, 76, 77, 90, 60, 41, 12, 30, 65]

>>> count(l3,6)

Number of steps 100

Answer 1

def count(lst, v):
    c = 0
    Nsteps = 0
    for item in lst:
        Nsteps += 1
        if item == v:
            c += 1
    print("Number of steps", Nsteps)
    return c


l3 = [52, 14, 14, 8, 85, 69, 1, 77, 94, 96, 51, 65, 35, 32, 87, 92, 74, 47, 27, 88, 11, 11, 26, 14, 100, 37, 62, 3, 63,
      5, 20, 53, 28, 10, 43, 16, 94, 6, 82, 49, 74, 55, 89, 97, 12, 38, 72, 94, 3, 77, 42, 26, 25, 16, 89, 10, 8, 63,
      93, 77, 68, 56, 74, 46, 54, 50, 80, 33, 69, 95, 2, 79, 73, 6, 31, 41, 38, 81, 88, 12, 39, 77, 49, 30, 18, 22, 40,
      40, 12, 51, 69, 32, 76, 77, 90, 60, 41, 12, 30, 65]
print(count(l3, 6))