Predict three (3) properties of a macroscopic amount of a chemical compound formed upon reaction of two (2) elements with each other whose difference in relative electronegativity (∆x) is 3.0. (Attempt to rationalize your answer.)
The reaction can be written as follows.
Li(s) + 1/2 F2(g)
LiF(s)
The electronegativity of Li = 0.98
The electronegativity of F = 3.98
The difference in relative electronegativity (∆x) = 3.98 - 0.98 = 3.0
The properties of lithium fluoride (LiF) are
(i) It's a white crystalline solid.
(ii) There are strong electrostatic forces of attraction between the oppositely charged ions (Li+ and F-)
(iii) It's an ionic compound with a high melting point.
(iv) Its structure is analogous to that of sodium chloride, but it is much less soluble in water.
The solubility of LiF in water = 1.34 g/L water
The solubility of NaCl in water = 360 g/L water
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