Question #7: Modes of inhibition determine the modes of inhibition of two inhibitors on an enzyme...
Question #7: Modes of inhibition determine the modes of inhibition of two inhibitors on an enzyme by using excel to graph the effects of the different inhibitors on the enzyme.
[S] (mM) No inhibitor 2 mM Inhibitor #1 100 mM Inhibitor #2
|
3 |
10.4 |
4.1 |
2.1 |
|
5 |
14.5 |
6.4 |
2.9 |
|
10 |
22.5 |
11.3 |
4.5 |
|
30 |
33.8 |
22.6 |
6.8 |
|
90 |
40.5 |
33.8 |
8.1 |
- What are the values of Vmax and Km in the absence of each inhibitor and in the presence of both inhibitors?
- What type of inhibition does each inhibitor exhibit?
Homework Answers
| [S] mM | 1/[S] 1/mM | V without inhibitor mM/min | 1/v without inhibitor min/mM | V with inhibitor 1 | 1/V with inhibitor 1 | V with inhibitor 2 | 1/V with inhibitor 2 |
| 3 | 0.33 | 10.4 | 0.09615 | 4.1 | 0.2439 | 2.1 | 0.4762 |
| 5 | 0.2 | 14.5 | 0.06897 | 6.4 | 0.1563 | 2.9 | 0.3448 |
| 10 | 0.1 | 22.5 | 0.04444 | 11.3 | 0.0885 | 4.5 | 0.2222 |
| 30 | 0.033 | 33.8 | 0.02959 | 22.6 | 0.0448 | 6.8 | 0.1471 |
| 90 | 0.011 | 40.5 | 0.02469 | 33.8 | 0.0296 | 8.1 | 0.1235 |
The equation of above Double reciprocal plot without inhibitor is :
y = 0.226x+0.022 (y = mx+c)
This can be compare to an equation 1/Vo = (Km/Vmax)1/[S] + 1/Vmax
Hence slope, m = Km/Vmax = 0.226
c = Y-intercept = 1/Vmax = 0.022
Vmax = 1/0.022 = 45.45 mM/min
Slope, m = Km/Vmax = 0.226
Km = 0.226 x 45.45 = 10.4977 mM
The equation of above Double reciprocal plot with inhibitor 1 is :
y = 0.671x+0.022 (y = mx+c)
This can be compare to an equation 1/Vo = (Km/Vmax)1/[S] + 1/Vmax
Hence slope, m = Km/Vmax = 0.671
c = Y-intercept = 1/Vmax = 0.022
Vmax = 1/0.022 = 45.45 mM/min ( It remained same)
Slope, m = Km/Vmax = 0.671
Km = 0.671 x 45.45 = 30.497 mM (It was increased)
The type of inhibition with inhibitor 1 is Competitive inhibition because Vmax is unaffected and Km is increased.
The equation of above Double reciprocal plot with inhibitor 1 is :
y = 1.118 x+0.112 (y = mx+c)
This can be compare to an equation 1/Vo = (Km/Vmax)1/[S] + 1/Vmax
Hence slope, m = Km/Vmax = 1.118
c = Y-intercept = 1/Vmax = 0.112
Vmax = 1/0.112 = 8.929 mM/min ( It was decreased)
Slope, m = Km/Vmax = 1.118
Km = 1.118 x 8.929 = 9.982 mM (It was decreased)
The type of inhibition with inhibitor 1 is Uncompetitive inhibition because both Vmax and Km are decreased.
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