A) A person borrows 10.000 $ at 8%
interest rate compounded annually and wishes to pay the loan back
over a five-
year period with annual payments. However, the second payment is to
be 500 $ greater than the first payment, the third
payment must be 1.000 $ greater than the second payment; the forth
payment must be 1.500 $ greater than the third
payment; and the fifth payment must be 2.000 $ greater than the
fourth payment. Determine the size of the first payment
and use Annual Equivalent approach in your solution.
B) X $ is borrowed from a bank. It is agreed that
payments of 2.000 $, 3.000 $, 4.000 $, and 5.000 $ made at
the
end of the 4th, 5th, 6th, and 7th years respectively will satisfy
the borrowed money if an interest rate of 10 % compounded
annually is the appropriate interest rate. By use of the uniform
gradient series factor and any other relevant interest
factor(s),
determine the amount of X $
C) A building will be constructed in 5 years. The yearly
expenditures in these five years will be 400.000 $/yr. The
building’s life is 40 years after the end of the construction. The
yearly net rental income during these 40 years will be
200.000
$/yr. Assuming an interest rate of 10 % in the first 20 years
(including 5 years of construction time and 15 years of the
building’s life) and an interest rate of 12 % in the remaining 25
years of the building’s life, calculate the value of the
building
at the end of its life.
D) A company wants to start an excavation business which will
continue for 11 years. They plan to buy an excavator
which will cost 620.000 $ with a useful life of 5 years and a
salvage value of 50.000 $. A major repair of 60.000 $ is estimated
for the end of the 3rd year. They also expect to get an income of
180.000 $ per year. At the end of the 5-year period, they
are planning to buy a new excavator for 800.000 $ with a useful
life of 6 years and a salvage value of 75.000 $. The expected
income from this excavator is 200.000 $ per year during its useful
life. Maintenance and repair cost for the second excavator
is expected to be 80.000 $ in the 3rd year of its useful life.
Interest rate for the first 5 years is 10% and for the next 6
years
interest rate is expected to be 12%. Decide whether this is a good
investment or not by calculating the present value of all
expected expenditures and incomes.
E) Solve any three questions above by using the financial functions
in Excel (You should write the commands and values )

As per HomeworkLib policy we need to answer only one question at once so please ask others as seperate one
A) A person borrows 10.000 $ at 8% interest rate compounded annually and wishes to pay...
1.Four years ago a person borrowed $15,000 at an interest rate of 10% compounded annually and agreed to pay it back in equal payments over a 10 year period. This same person now wants to pay off the remaining amount of the loan. How much should this person pay? Assume that she has just made the 3rd payment. 2.What is the accumulated amount resulting from a series of equal yearly deposits of $1,000 for 6 years if the interest rate...
-27 How much invested now at an interest rate of 9% compounded annually would be just sufficient to provide three payments as follows: the first payment in the amount of $3,000 occurring two years from now, the second payment in the amount of $4,000 five years thereafter, and the third payment in the amount of $5,000 seven years thereafter? 62.34 What is the future worth of a series of equal yearly deposits of $5,000 for 7 years in a savings...
RM60,000 is borrowed for 12 years at 5% compounded annually. The borrower does not pay interest currently and will pay all accrued interest at the end of 12 years together with the principal. (a) Find the amount annual sinking fund deposit necessary to liquidate the loan at the end of 12 years if the sinking fund earns 3% yearly compounding and the borrower make first payment immediately. (b) Prepared a sinking fund schedule. Ans: (a) RM 7,371.25 (PLS DUN ANSWER...
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- A person borrows $5000 from a bank at an interest rate of 10% caupounded yearly and pays it buck in 8 years. If the person makes the following payments starting at the end of the 2nd year to the end of 7th year $500 $500 $475, $450, $425, $425, then what is the amount of the last payment so that the loan is paid off? Note: must ux discrete, uniform serres, and gradient series.
A company has
borrowed 1,000,000 from a bank which charges 14 % interest per
annum. The loan has to be recovered in 5 years compounded
annually
(a) How much
should the company pay at the end of each year to the bank
(assuming uniform payment)?
(b) The bank
changes the interest rate to 13 % p.a . at the beginning of 3rd
year
(i) What will
the amount of the company's last payment (i.e. payment at the end
of year...
A business man borrowed P10000 with interest at the rate of 5% payable annually. The debt will be paid, principal and interest included, by equal payments at the end of each year for 5 years. Compute the annual payment and construct the amortization schedule.
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Question 8 1 pts At what periodic interest rate is $2.000 cash receipt occurring at the beginning of year 1 equivalent to 4 annual 5600 cash disbursements? The first cash disbursement occurs at the end of year 1, the second occurs at the end of year 2, the third occurs at the end of year 3. and the fourth occurs at the end of year 4. The periodic interest rate is compounded annually. 5.33% 7.71%...
You have borrowed $50,000 at an interest rate of 12%. Equal payments will be made over a three-year period. (The first payment will be made at the end of the first year.) What will the annual payment be, and what will the interest payment be for the second year?
You borrow $11,000 from the bank at an interest rate of 6%, compounded annually. You are required to make 10 equal end of-year payments to pay off the loan. a) What is the amount of these equal payments? b) What is the amount of the 10 payments if the first payment is not made until 3 years after receipt of the money?
Calculate the future worth of the purchase shown below using an interest rate of 6% per year. First Cost: -$17,000 Operating Cost: -$3,000/YR Salvage Value: $2,000 Useful Life: 7 Years