Question

A simple harmonic oscillator is made up of a mass-spring system, with mass of 2.12 kg and a spring constant k = 103 N/m. At time t=1.38 s, the position and velocity of the block are x = 0.116 m and v = 3.516 m/s. What is the velocity of the oscillation at t=0? Be sure to include the minus sign for negative velocity.

Your answer should be in m/s, but enter only the numerical part in the box.

Answer 1

SOLUTION:

Given that:

Mass of the block, m = 2.12 kg

Spring constant, K = 103 N/m

Therefore, Angular speed of SHO is given by:

For SHO, displacement at a time t is given by:

Given that, at t = 1.38 s, x (t) = 0.116 m

Therefore, Amplitude of motion is given by:

Now the speed of the SHO is given by:

Hence, Velocity of the oscillation at t = 0s is given by: