A solution containing an unknown amount of palmitic acid in 10.0 g stearic acid depressed the freezing point by 3.8oC. How much palmitic acid, in grams, is in this solution?
A solution containing an unknown amount of palmitic acid in 10.0 g stearic acid depressed the...
1.0345 g of palmitic acid dissolved in 8.7545 g of stearic acid. Calculate the freezing point of the solution. The molar mass of palmitic acid is 256.48 g/ mol. The molal freezing point constant , Kf for stearic acid is 4.5 degrees C/ m and pure stearic acid freezes at 69.3 degrees Celsius.
1. The stearic acid/hexane solution contains 0.1 g of stearic acid per 1 mL of solution. What is the molarity of this solution?
LIPIDS a. Draw a triglyceride containing palmitic, stearic, and oleic acids, identify each one. b. Consider a triglyceride containing three oleic acids: compare its melting point and iodine number to the triglyceride in (a); describe how hydrogenation would affect these attributes. C. Draw the chemical structures of phosphatidylcholine and sphingomyelin; explain their similarities and differences, including the types of water-labile linkages (bonds) present in each. d. What is meant by "good cholesterol" and "bad cholesterol?" e. How do manufacturers get...
An aqueous solution containing 17.5 g of an unknown molecular compound in 100.0 g of water was found to have a freezing point of -1.8
An aqueous solution containing 35.9 g of an unknown molecular compound in 150.0 g of water was found to have a freezing point of -1.3 degree C. Calculate the molar mass of the unknown compound.
An aqueous solution containing 16.5 g of an unknown molecular (nonelectrolyte) compound in 105.5 g of water was found to have a freezing point of -1.5 ∘C. Calculate the molar mass of the unknown compound.
Calculate the freezing point and boiling point of a solution containing 10.0 g of naphthalene (C10Hz) in 100.0 mL of benzene. Benzene has a density of 0.877 g/cm².
An aqueous solution containing 17.3 g of an unknown molecular (nonelectrolyte) compound in 102.0 g of water was found to have a freezing point of -1.6 ?C. Part A Calculate the molar mass of the unknown compound.
A solution containing 3.50 g of an unknown nonelectrolyte liquid and 9.90 g water has a freezing point of −3.33 °C. The Kf = 1.86 °C/m for water. Calculate the molar mass of the unknown liquid in g/mol
An aqueous solution containing 16.2 g of an unknown molecular (nonelectrolyte) compound in 109.5 g of water was found to have a freezing point of -1.8 ∘C. Calculate the molar mass of the unknown compound. Please show all work.