Suppose that the time required to complete a 1040R tax form is normally distributed with a mean of 90 minutes and a standard deviation of 10 minutes. What proportion of 1040R tax forms will be completed in less than 85 minutes? Round your answers to at least four decimal places.
Solution :
Given that ,
mean =
= 90
standard deviation =
= 10
P(X<85 ) = P[(X-
) /
< (85-90) / 10]
= P(z <-0.5 )
Using z table
proportion = 0.3085
Suppose that the time required to complete a 1040R tax form is normally distributed with a...
Suppose that the time required to complete a 1040R tax form is normally distributed with a mean of 100 minutes and a standard deviation of 10 minutes. What proportion of 1040R tax forms will be completed in more than 102 minutes? Round your answer to at least four decimal places X
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D Incorrect Your answer is incorrect. Suppose that the time required to complete a 1040R tax form is normally distributed with a mean of 100 minutes and a standard deviation of 15 minutes. What proportion of 1040R tax forms will be completed in at most 81 minutes? Round your answer to at least four decimal places. E 0.8980 5 ?
5 6 7 8 ✓9 F 10 ✓ 11 Incorrect Your answer is incorrect. Suppose that the time required to complete a 1040R tax form is normally distributed with a mean of 100 minutes and a standard deviation of 15 minutes. What proportion of 1040R tax forms will be completed in at most 81 minutes? Round your answer to at least four decimal places. 0.1020 X 5 2
Answer question 1 & 2 asap please
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