(I know how to get the number answer through a work equation but..I don't know why)...
(I know how to get the number answer through a work equation but..I don't know why) If gas expanded from 30L to 70L against a pressure of 2.8atm why would the internal energy be less? Wouldn't the internal energy be the same but more spread out as heat over a larger volume decreasing kinetic energy and there for having a lower pressure, but the same amount of total energy started with is still present within the system.
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(I know how to get the number answer through a work equation
but..I don't know why)...
(I know how to get the number answer through a work equation but..I don't know why) If gas expanded from 30L to 70L...
(I know how to get the number answer through a work equation but..I don't know why) If gas expanded from 30L to 70L against a pressure of 2.8atm why would the internal energy be less? Wouldn't the internal energy be the same but more spread out as heat over a larger volume decreasing kinetic energy and there for having a lower pressure, but the same amount of total energy started with is still present within the system.
= = = = = =I have the answer, but I don't know how to get...
=
=
=
=
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=I have the answer, but I don't know how to get it. Please show
me how to do. thanks
I have the answer, but I don't know how to get it. Please show
me how to do. thanks
I have the answer, but I don't know how to get it. Please show
me how to do. thanks
I have the answer, but I don't know how to get it. Please show
me how to do....
FYI, the answer is not in the answer choice. Instead, it is -894J but I do...
FYI, the answer is not in the answer choice. Instead, it is
-894J but I do not know how to solve the problem
14. The total internal energy change for a gas is -1500. J. If it expanded from 1.000 liters to 5.000 liters against a pressure of 1.500 atm, what was the change in heat for the system? (1.00 L'atm = 101.0 J) 1) +1506 J 2) -1506.J 3) -2106. J 4) +2106.J
I know the answer is e but I don't understand how to get there. Relevant equations...
I know the answer is e but I don't understand how to get
there.
Relevant equations may include:
e 9. [6 points] In a cell, chemical potential of phase 2 against phase 1 was measured at temperature T [K]. (ie, phase changed from phase 1 to phase 2) If this chemical potential is Δμ, what is the ratio of osmotic pressure between phase 2 and phase l (112 / П.) at T [K]? Assume that the activity of phase 1...
I don't know why the answer is wrong, I got K(final) = 1.1072x10^-15 J and K(initial)...
I don't know why the answer is
wrong, I got K(final) = 1.1072x10^-15 J and K(initial) =
1.4576x10^-15J, with the work energy theorm I got q=(Kf-Ki)/(Vi-Vf)
= +5.48x10^-18 C
Your answer is partially correct. Try again. A moving particle encounters an external electric field that decreases its kinetic energy from 9100 eV to 6990 eV as the particle moves from position A to position B. The electric potential at A is-41.0 V, and that at B is +23.0 V. Determine...
I know the answer is 0.425 m, but I don't know how to get there. Also...
I know the answer is 0.425 m, but I don't know how to
get there. Also if possible to solve by using Energy that method
would be preferred.
02. 3/104 from the book (just part b). The system shown in the figure below has a spring two masses and two massless pulleys. The pulley cords are massless and inextensible. The system is released from rest and with the spring stretched 200 mm. Determine the distances traveled by the 4 kg...
I know the answers but I don't know how to solve the work. Please show the...
I know the answers but I don't know how to solve the work.
Please show the work
1.)
Answer: D
2.)
Answer: D
3.)
Answer: A
Aluminum has a specific heat of 0.902 J/g.°C. How many joules of heat are required to change the temperature of 8.50 grams of aluminum from 25.0°C to 93.4°C? a. 7.67 J b. 71.7 J c. 192J d. 524 J Water has a specific heat of 4.18 J/g. °C. If 35.0 g of water at...
#51. i know the answer but i don't know how to get it. please explain. thx...
#51. i know the answer but i don't know how to get it. please
explain. thx
For questions 51-53 use this diagram given that CB and CD are opposite rays, CE bisects LDCF, and CG bisects LFCB. 51. If mLDCE = 4x + 15 and mLECF= 6x-5, ind mDCE mLDCE-55 52. If mLFCG9x3 and mzGCB 13x- 9, find mzGCB mZGCB-30
I know the answer is A, just don't know how to get there. Please show full...
I know the answer is A, just don't know how to get there. Please
show full solution! Thanks
8. 0.625 Pi A billiard ball is moving along the tx axis with constant speed. It collides with a second similar ball which is at rest. After the collision each ball possesses 62.5% of the initial amount of momentum, Pi (see diagram). - - -- X 0.625 Pi Find the angle e. (a) 36.90 (b) 53.1° c ) Neither of these
The correct answer is E but I don't know how to get to that number. 11...
The correct answer is E but I don't know how to get to that
number.
11 Our company makes and sells three products: A, B, and C. Selected GAAP income statement information is below: 20,000 $300,000 $100,000 5,000 $500,000 $150,000 10,000 $450,000 $160,000 Units sold Sales Gross margin Fixed Manufacturing Costs allocated to products by machine hours Fixed Non-Manufacturing Costs allocated to products by various methods GAAP Net Operating Income by products $40,000 $198.000 $77,100 $68,900 $11,100 $70,800 $31,200 $21,000...
=
=
=
=
=
=I have the answer, but I don't know how to get it. Please show
me how to do. thanks
I have the answer, but I don't know how to get it. Please show
me how to do. thanks
I have the answer, but I don't know how to get it. Please show
me how to do. thanks
I have the answer, but I don't know how to get it. Please show
me how to do....
FYI, the answer is not in the answer choice. Instead, it is
-894J but I do not know how to solve the problem
14. The total internal energy change for a gas is -1500. J. If it expanded from 1.000 liters to 5.000 liters against a pressure of 1.500 atm, what was the change in heat for the system? (1.00 L'atm = 101.0 J) 1) +1506 J 2) -1506.J 3) -2106. J 4) +2106.J
I know the answer is e but I don't understand how to get
there.
Relevant equations may include:
e 9. [6 points] In a cell, chemical potential of phase 2 against phase 1 was measured at temperature T [K]. (ie, phase changed from phase 1 to phase 2) If this chemical potential is Δμ, what is the ratio of osmotic pressure between phase 2 and phase l (112 / П.) at T [K]? Assume that the activity of phase 1...
I don't know why the answer is
wrong, I got K(final) = 1.1072x10^-15 J and K(initial) =
1.4576x10^-15J, with the work energy theorm I got q=(Kf-Ki)/(Vi-Vf)
= +5.48x10^-18 C
Your answer is partially correct. Try again. A moving particle encounters an external electric field that decreases its kinetic energy from 9100 eV to 6990 eV as the particle moves from position A to position B. The electric potential at A is-41.0 V, and that at B is +23.0 V. Determine...
I know the answer is 0.425 m, but I don't know how to
get there. Also if possible to solve by using Energy that method
would be preferred.
02. 3/104 from the book (just part b). The system shown in the figure below has a spring two masses and two massless pulleys. The pulley cords are massless and inextensible. The system is released from rest and with the spring stretched 200 mm. Determine the distances traveled by the 4 kg...
I know the answers but I don't know how to solve the work.
Please show the work
1.)
Answer: D
2.)
Answer: D
3.)
Answer: A
Aluminum has a specific heat of 0.902 J/g.°C. How many joules of heat are required to change the temperature of 8.50 grams of aluminum from 25.0°C to 93.4°C? a. 7.67 J b. 71.7 J c. 192J d. 524 J Water has a specific heat of 4.18 J/g. °C. If 35.0 g of water at...
#51. i know the answer but i don't know how to get it. please
explain. thx
For questions 51-53 use this diagram given that CB and CD are opposite rays, CE bisects LDCF, and CG bisects LFCB. 51. If mLDCE = 4x + 15 and mLECF= 6x-5, ind mDCE mLDCE-55 52. If mLFCG9x3 and mzGCB 13x- 9, find mzGCB mZGCB-30
I know the answer is A, just don't know how to get there. Please
show full solution! Thanks
8. 0.625 Pi A billiard ball is moving along the tx axis with constant speed. It collides with a second similar ball which is at rest. After the collision each ball possesses 62.5% of the initial amount of momentum, Pi (see diagram). - - -- X 0.625 Pi Find the angle e. (a) 36.90 (b) 53.1° c ) Neither of these
The correct answer is E but I don't know how to get to that
number.
11 Our company makes and sells three products: A, B, and C. Selected GAAP income statement information is below: 20,000 $300,000 $100,000 5,000 $500,000 $150,000 10,000 $450,000 $160,000 Units sold Sales Gross margin Fixed Manufacturing Costs allocated to products by machine hours Fixed Non-Manufacturing Costs allocated to products by various methods GAAP Net Operating Income by products $40,000 $198.000 $77,100 $68,900 $11,100 $70,800 $31,200 $21,000...
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