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To better characterize your Valentine’s Day dinner wine, calculate ∆S for the following process involving ethanol:...

To better characterize your Valentine’s Day dinner wine, calculate ∆S for the following process involving ethanol:

1 mol CH3CH2OH(l), 25°C  1 mol CH3CH2OH(g), 100°C.

The boiling point of ethanol is 78.4°C.

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Answer #1

Entropy change of vaporization of one mole of ethanol = ∆Hvap/Tboil,

∆Hvap= 38.56kj /mol

= 38560/(273+78.4)

= 109.73 J/k is the entropy change for the process

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