2 H2S(g) ⇄ 2 H2(g) + S2(g) Kc = 9.3× 10^-8 at 400ºC 0.47 moles of...

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Question

2 H2S(g) ⇄ 2 H2(g) + S2(g) Kc = 9.3× 10^-8 at 400ºC

0.47 moles of H2S are placed in a 3.0 L container and the system is allowed to reach equilibrium. Calculate the concentration of H2 at equilibrium.

THE ANSWER IS : 1.7x10^(-3)

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Answer 1

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