Question

Calculate how many mL of 6M HCl acid were actually required to react with your sample of CuO? approximately what percentage excess did you use?

sample 0.188 g of CuO.

Answer 1

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Given reaction:

From the above reaction we have, 1 mol of CuO reacts with 2 mol of HCl.

Given mass of CuO = 0.188 g

Molar mass of CuO,= 79.545 g/mol/

Therefore, no.of moles of CuO in the sample is given by,

Therefore no.of moles of HCl required = 2 x n= 0.0042688 mol.

Therefore, Volume of HCl required is given by,

We have, 1 L = 1000 mL

Excess percentage is given by the equation:

For example:

Let volume used is 36 mL.

Then, Excess percentage is given by

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