Question

A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.67 ​hours, with a standard deviation of 2.45

hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.36 ​hours, with a standard deviation of 1.72 hours. Construct and interpret a 90% confidence interval for the mean difference in leisure time between adults with no children and adults with children (u1−μ2).

Let μ1 represent the mean leisure hours of adults with no children under the age of 18 and μ2 represent the mean leisure hours of adults with children under the age of 18.The 90% confidence interval for (μ1−μ2) is the range from ____ hours to ____hours.

Interpret the interval:

Answer 1

Confidence interval :-

DF = 69



Lower Limit =
Lower Limit = 0.5209
Upper Limit =
Upper Limit = 2.0991
90% Confidence interval is ( 0.5209 , 2.0991 )

We are 90% confident that the mean difference in leisure time between adults with no children and adults with children lies in the interval ( 0.5209 , 2.0991 ).