A drugstore uses fixed-order cycles for many of the items it stocks. The manager wants a service level of .99. The order interval is 12 days, and lead time is 4 days. Average demand for one item is 63 units per day, and the standard deviation of demand is 6 units per day. Given the on-hand inventory at the reorder time for each order cycle shown in the following table.
| Cycle | On Hand |
| 1 | 38 |
| 2 | 10 |
| 3 | 93 |
Determine the order quantities for cycles 1, 2, and 3.
Given values:
Service level = 0.99
Daily demand (d) = 63 units per day
Time between orders (T) = 12 days
Lead time (L) = 4 days
Standard deviation of demand, Sigma (d) = 6 units per day
Solution:
Using NORMSINV function in MS Excel, value of Z can be determined.
Z = NORMSINV (Service level)
Z = NORMSINV (0.99)
Z = 2.33
Order Quantity (Q) is calculated as,
Q = d (T + L) + Z Sigma (T + L) - I
where,
I = On-hand inventory
Sigma (T + L) = Sigma (d) x SQRT (T + L)
Sigma (T + L) = 6 x SQRT (12 + 4)
Sigma (T + L) = 24
Putting the given values in the above formula, we get,
Q = d (T + L) + Z Sigma (T + L) - I
Q = [63 x (12 + 4)] + [2.33 x 24] - I
Q = 1008 + 55.92 - I
Q = 1063.92 - I
Order quantity for period 1:
Order quantity (cycle 1) = 1063.92 - 38
Order quantity (cycle 1) = 1025.92 or 1026 (Rounding off to the nearest whole number)
Order quantity (cycle 1) = 1,026 units
Order quantity for period 2:
Order quantity (cycle 2) = 1063.92 - 10
Order quantity (cycle 2) = 1053.92 or 1054 (Rounding off to the nearest whole number)
Order quantity (cycle 2) = 1,054 units
Order quantity for period 3:
Order quantity (cycle 3) = 1063.92 - 93
Order quantity (cycle 3) = 970.92 or 971 (Rounding off to the nearest whole number)
Order quantity (cycle 3) = 971 units
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