t-Test: Two-Sample Assuming Unequal Variances
A two-sample test for means was conducted to test whether the mean number of movies watched each month differed between males and females. The Excel Data Analysis tool results are shown below.
| Female | Male | |
| Mean | 5.6 | 7.5 |
| Variance | 6.267 | 21.833 |
| Observations | 10 | 10 |
| Hypothesized Mean Difference | 0 | |
| DF | 14 | |
| T Stat | -1.133 | |
| P(T<=t) One-Tail | 0.138 | |
| t Critical One-Tail | 1.76 | |
| P(T<=t) Two-Tail | 0.276 | |
| t Critical Two-Tail | 2.144 | |
a. Explain how to use this information to draw a conclusion if the null hypothesis is H0: µF - µM <= 0. Clearly state the correct critical value and p-value and your conclusion.
b. Explain how to use this information to draw a conclusion if the null hypothesis is H0: µF - µM >= 0. Clearly state the correct critical value and p-value and your conclusion.
c. Explain how to use this information to draw a conclusion if the null hypothesis is H0: µF - µM = 0. Clearly state the correct critical value and p-value and your conclusion.
a) This is a one-tailed test, however since this is a lower tailed test, the critical value will be negative
| P(T<=t) One-Tail | 0.138 |
| t Critical One-Tail | -1.76 |
The hypothesis cannot be rejected as the p-value is not significant
b) This is a one-tailed test
| P(T<=t) One-Tail | 0.138 |
| t Critical One-Tail | 1.76 |
The hypothesis cannot be rejected as the p-value is not significant
c) This is a two-tailed test
| P(T<=t) Two-Tail | 0.276 | |
| t Critical Two-Tail | 2.144 |
The hypothesis cannot be rejected as the p-value is not significant
t-Test: Two-Sample Assuming Unequal Variances A two-sample test for means was conducted to test whether the...
Do a two-sample test for equality of means assuming unequal variances. Calculate the p-value using Excel. (a-1) Comparison of GPA for randomly chosen college juniors and seniors: x⎯⎯1x1 = 4.75, s1 = .20, n1 = 15, x⎯⎯2x2 = 5.18, s2 = .30, n2 = 15, α = .025, left-tailed test. (Negative values should be indicated by a minus sign. Round down your d.f. answer to the nearest whole number and other answers to 4 decimal places. Do not use "quick"...
Do a two-sample test for equality of means assuming unequal variances. Calculate the p-value using Excel. (a-1) Comparison of GPA for randomly chosen college juniors and seniors: x⎯⎯1x1 = 4.75, s1 = .20, n1 = 15, x⎯⎯2x2 = 5.18, s2 = .30, n2 = 15, α = .025, left-tailed test. (Negative values should be indicated by a minus sign. Round down your d.f. answer to the nearest whole number and other answers to 4 decimal places. Do not use "quick"...
Do a two-sample test for equality of means assuming unequal variances. Calculate the p-value using Excel. (a-1) Comparison of GPA for randomly chosen college juniors and seniors: x⎯⎯1x1 = 4.75, s1 = .20, n1 = 15, x⎯⎯2x2 = 5.18, s2 = .30, n2 = 15, α = .025, left-tailed test. (Negative values should be indicated by a minus sign. Round down your d.f. answer to the nearest whole number and other answers to 4 decimal places. Do not use "quick"...
Do a two-sample test for equality of means assuming unequal variances. Calculate the p-value using Excel. (a-1) Comparison of GPA for randomly chosen college juniors and seniors: x⎯⎯1 = 4, s1 = .20, n1 = 15, x⎯⎯2 = 4.25, s2 = .30, n2 = 15, α = .025, left-tailed test. (Negative values should be indicated by a minus sign. Round down your d.f. answer to the nearest whole number and other answers to 4 decimal places. Do not use "quick"...
Do a two-sample test for equality of means assuming unequal variances. Calculate the p-value using Excel. (a-1) Comparison of GPA for randomly chosen college juniors and seniors: x⎯⎯1 = 4, s1 = .20, n1 = 15, x⎯⎯2 = 4.25, s2 = .30, n2 = 15, α = .025, left-tailed test. (Negative values should be indicated by a minus sign. Round down your d.f. answer to the nearest whole number and other answers to 4 decimal places. Do not use "quick"...
Do a two-sample test for equality of means assuming unequal variances. Calculate the p-value using Excel. (a-1) Comparison of GPA for randomly chosen college juniors and seniors: x⎯⎯1 = 4, s1 = .20, n1 = 15, x⎯⎯2 = 4.25, s2 = .30, n2 = 15, α = .025, left-tailed test. (Negative values should be indicated by a minus sign. Round down your d.f. answer to the nearest whole number and other answers to 4 decimal places. Do not use "quick"...
t-Test: Two-Sample Assuming Equal Variances Variable 1 Variable 2 Mean 12.89795918 17.66666667 Variance 161.2185374 567.8266667 Observations 49 51 Pooled Variance 368.6716646 Hypothesized Mean Difference 0 Df 98 t Stat -1.241549191 P(T<=t) one-tail 0.108683158 t Critical one-tail 1.660551217 P(T<=t) two-tail 0.217366316 t Critical two-tail 1.984467455 Is there a significant difference between the two sample means? If you answer, “yes,” what is your reasoning? If you answer, “no,” what is your reasoning? Please state the conclusion, or your interpretation of the results in terms...
Stress between males and females
*Note: alpha = .001
1 t-Test: Two-Sample Assuming Unequal Variances Female Male 4 Mean 5 Variance 6 Observations 7 Hypothesized Mean Difference 3.655737705 3.52857143 1.296174863 1.12236025 70 61 8 df 9 t Stat 10 P(T-t) one-tail 11 t Critical one-tail 12 P(T<-t) two-tail 13 t Critical two-tail 124 0.658596658 0.255687918 3.157259054 0.511375836 3.370720124 Student Survey Data (2 Sample t-test) 1. Test Decision & Basis 2. Interpretation of Test Decision:
A hypothesis test is conducted to test the null hypothesis that the mean is less than 12. Use a 0.01 level of significance. What type of test is this? Right tail Two tail Left tail What is the critical value? 2.33 -2.33 1.78 correct answer is not given Suppose the test statistic was -2.50 What is the conclusion? Fail to reject Ho. There is not sufficent evidence to support the claim that the mean is less than 12. Reject Ho....
t-test: two-sample assuming equal variances Subject ID Height Mean 9.9 68.85 Variance 39.0421053 35.0815789 Observations 20 20 Pooled Variance 37.0618421 Hypothesized Mean Difference 0 df 38 t Stat -30.621066 P(T<=t) one-tail 1.0856E-28 t Critical one-tail 1.68595446 P(T<=t) two-tail 2.1711E-28 t Critical two-tail 2.02439416 From your results, please report the following: Variable 1 Mean: Variable 2 Mean: Two-tailed p-value: Is your p-value significant? (alpha=0.05) If your results are significant/not significant, what can you conclude from your data? (i.e. is there a...