iii. 2Fe2++ MnO2(s)+ 4H2Oßà2Fe(OH)3(s)+ Mn2++ 2H+ (d) Let’s take reaction b(iii) and measure the true Fe2+,...
iii. 2Fe2++ MnO2(s)+ 4H2Oßà2Fe(OH)3(s)+ Mn2++ 2H+
(d) Let’s take reaction b(iii) and measure the true Fe2+, Mn2+and pH of the environment.
We find that Fe2+= 10-6M, Mn2+ = 10-6M and pH = 8.
Use the Nernst equation to determine the environmental E (instead of E0) for each of your half reactions for Fe and Mn. (10 points)
Now what is the real DG0of reaction b(iii) under environmental conditions? (5 points)
Homework Answers
Add Answer to:
iii. 2Fe2++ MnO2(s)+
4H2Oßà2Fe(OH)3(s)+ Mn2++
2H+
(d) Let’s take reaction b(iii) and measure the true
Fe2+,...
Consider the two following half reactions: Fe(OH)3(s) + 3H3O+ + e- <-> Fe2+(aq)+ 6H2O EoH= 1.06...
Consider the two following half reactions: Fe(OH)3(s) + 3H3O+ + e- <-> Fe2+(aq)+ 6H2O EoH= 1.06 V; peo= 17.9 NO3-(aq) + 10H3O+ + 8e- <-> NH4+(aq)+ 13H2O EoH= 0.88V; peo= 14.9 (a)Which reaction would you expect to be the oxidation and which the reduction under standard conditions? (b)Write the full balanced reaction.Show your work. (c)Assuming that the concentrations ofFe2+(aq), NH4+(aq), and NO3-(aq) are all 10-5M and pH 7, calculate the pE for the redox reaction in (b). (d)Comment on what...
A) Use tabulated electrode potentials to calculate ΔG∘ for the reaction. 2K(s)+2H2O(l)→H2(g)+2OH−(aq)+2K+(aq) B) (Refer to the...
A) Use tabulated electrode potentials to calculate ΔG∘ for the reaction. 2K(s)+2H2O(l)→H2(g)+2OH−(aq)+2K+(aq) B) (Refer to the following standard reduction half-cell potentials at 25∘C: VO2+(aq)+Ni2+(aq)2H+(aq)++2e−e−→ →Ni(s)VO2+(aq) +H2O(l)E∘=−0.23V E∘=0.99V) An electrochemical cell is based on these two half-reactions: Oxidation:Reduction:Ni(s)VO2+(aq,0.024M)+2H+(aq,1.4M)+e−→→Ni2+(aq,1.8M)+2e−VO2+(aq,1.8M)+H2O(l) Calculate the cell potential under these nonstandard concentrations. C) Standard reduction half-cell potentials at 25∘C Half-reaction E∘ (V ) Half-reaction E∘ (V ) Au3+(aq)+3e−→Au(s) 1.50 Fe2+(aq)+2e−→Fe(s) − 0.45 Ag+(aq)+e−→Ag(s) 0.80 Cr3+(aq)+e−→Cr2+(aq) − 0.50 Fe3+(aq)+3e−→Fe2+(aq) 0.77 Cr3+(aq)+3e−→Cr(s) − 0.73 Cu+(aq)+e−→Cu(s) 0.52 Zn2+(aq)+2e−→Zn(s) − 0.76...
A chemist designs a galvanic cell that uses these two half-reactions: standard reduction potential half-reaction +...
A chemist designs a galvanic cell that uses these two half-reactions: standard reduction potential half-reaction + O2(9)+4 H (aq)+4e' 2H20) = 1.23 V red Ered Fe+. (аq) Fe3(aq)+e = +0.771 V Answer the following questions about thiss cell Write a balanced equation for the half-reaction that happens at the cathode Write a balanced equation for the half-reaction that happens at the anode Write a balanced equation for the overall reaction that powers the cell. Be sure the reaction is spontaneous...
helpp 3. For the hypothetical reaction A+B → C the following rate data (with and without...
helpp
3. For the hypothetical reaction A+B → C the following rate data (with and without catalyst) were obtained: Rate, M/s Rate, M/s ALM B., Muncatalyzed) (catalyzed) 0.100 0.200 3.51 x 10 7.14 x 10 0.100 0.100 1.75 x 10 7.14 x 10 0.0500 0.200 1.76 x 10 3.57 x 10 0.0500 0.100 8.80 x 10 3.57 x 10 Based on these data: a. Determine the uncatalyzed and catalyzed rate laws for this reaction, and the corresponding rate constants. (16...
5. How much faster would a reaction be if a catalyst is used that lowers the...
5. How much faster would a reaction be if a catalyst is used that lowers the activation energy from 20.0 kJ/mol to 10.0 kJ/mol? Do the calculation at two temperatures: first at 25.0°C and then at 0.0°C. (20 points) (V) Helpful Stuff Thermodynamics: AG° = AH-TAS Nernst Equation: 6 = 6 - (RT/nF)InQ AG=RTIK At 25°C: 8 = 6 - (0.0591/n)logQ AGRT Ke=e AGⓇ =-nF8° Units/Constants: Volt: 1 V = 1 J/C Faraday: 1 F = 96,485 C/mole Arrhenius Equation:...
7. Using the following reaction progress diagram, answer the questions below: wiring Energy A G Rxn....
7. Using the following reaction progress diagram, answer the questions below: wiring Energy A G Rxn. a. How many steps are in the reaction? How do you know? (4 points) b. Which letter corresponds to the rate-determining-step? Explain your choice. (6 points) c. Is the reaction exothermic or endothermic? How do you know? (4 points) d. If the energy at point B is lowered, what will happen to the rate of the reaction will it increase, decrease, or stay the...
problem 9 D . the answer is 99.1 I don’t know how to do problem please...
problem 9 D . the answer is 99.1 I don’t know how to do problem
please show step by step
Problems | 261 E of 9. ng it to anide onsider the following reaction, in which two electrons are transferred from cytochrome-c (reduced) 2cyt c[Fe2+] +pyruvate 2H- 2cyt c[Fe3 + lactate for this reaction at p a. What is b. Calc H 7 and 25°C? ically, ulate the equilibrium constant for the reaction at pH 7 and 25°C. c. Calculate...
help!! (CH3),CBr + 1 → (CH3),CI + Br the following data were collected: [(CH3)3Br] (M) Time...
help!!
(CH3),CBr + 1 → (CH3),CI + Br the following data were collected: [(CH3)3Br] (M) Time (s) 0.600 0 0.424 10.0 0.300 20.0 0.212 30.0 0.150 40.0 Determine the rate law for this reaction and calculate the rate constant. (20 points) E (V) Thermodynamics: AGº - AH-TAS Nernst Equation: 8 = 8°-(RT/nF)InQ AGⓇ--RTINK At 25°C: 8-6° -0.0591/n)logQ AG RT K-e AG° = -nF8° Units/Constants: Volt: 1 V-1 JC Faraday: 1 F -96,485 C/mole Ea/RT Arrhenius Equation: k = Ae R-8.314...
need help with the rest of the table EXPERIMENT 10 DETERMINATION OF THE ELECTROCHEMICAL SERIES PURPOSE...
need help with the rest of the table
EXPERIMENT 10 DETERMINATION OF THE ELECTROCHEMICAL SERIES PURPOSE To determine the standard cell potential values of several electrochemical coll INTRODUCTION The basis for an electrochemical cell is an oxidation reduction Corredor be divided into two half reactions reaction. This reaction can Oxidation half reaction Gloss of electrons) takes place at the anode, which is the positive electrode that the anions migrate to Chence the name anode) Reduction half reaction (gain of electrons)...
What results when a secondary alcohol is oxidized? a. a ketone d. an acid b. an...
What results when a secondary alcohol is oxidized? a. a ketone d. an acid b. an amine e. no reaction c. an aldehyde Which of the following combinations will react spontaneously? A. 12 + Cu2+ B. Pb2+ + Ag C. Zn2+ + Mg D. Sn2+ + Ni2+ The general formula for a cycloalkane can be represented by which of the following? a. C,H, C. CH b. C.H2n+2 d. C.H21-2 In a certain reaction AH =-136 kJ and E, = 96...
A chemist designs a galvanic cell that uses these two half-reactions: standard reduction potential half-reaction + O2(9)+4 H (aq)+4e' 2H20) = 1.23 V red Ered Fe+. (аq) Fe3(aq)+e = +0.771 V Answer the following questions about thiss cell Write a balanced equation for the half-reaction that happens at the cathode Write a balanced equation for the half-reaction that happens at the anode Write a balanced equation for the overall reaction that powers the cell. Be sure the reaction is spontaneous...
helpp
3. For the hypothetical reaction A+B → C the following rate data (with and without catalyst) were obtained: Rate, M/s Rate, M/s ALM B., Muncatalyzed) (catalyzed) 0.100 0.200 3.51 x 10 7.14 x 10 0.100 0.100 1.75 x 10 7.14 x 10 0.0500 0.200 1.76 x 10 3.57 x 10 0.0500 0.100 8.80 x 10 3.57 x 10 Based on these data: a. Determine the uncatalyzed and catalyzed rate laws for this reaction, and the corresponding rate constants. (16...
5. How much faster would a reaction be if a catalyst is used that lowers the activation energy from 20.0 kJ/mol to 10.0 kJ/mol? Do the calculation at two temperatures: first at 25.0°C and then at 0.0°C. (20 points) (V) Helpful Stuff Thermodynamics: AG° = AH-TAS Nernst Equation: 6 = 6 - (RT/nF)InQ AG=RTIK At 25°C: 8 = 6 - (0.0591/n)logQ AGRT Ke=e AGⓇ =-nF8° Units/Constants: Volt: 1 V = 1 J/C Faraday: 1 F = 96,485 C/mole Arrhenius Equation:...
7. Using the following reaction progress diagram, answer the questions below: wiring Energy A G Rxn. a. How many steps are in the reaction? How do you know? (4 points) b. Which letter corresponds to the rate-determining-step? Explain your choice. (6 points) c. Is the reaction exothermic or endothermic? How do you know? (4 points) d. If the energy at point B is lowered, what will happen to the rate of the reaction will it increase, decrease, or stay the...
problem 9 D . the answer is 99.1 I don’t know how to do problem
please show step by step
Problems | 261 E of 9. ng it to anide onsider the following reaction, in which two electrons are transferred from cytochrome-c (reduced) 2cyt c[Fe2+] +pyruvate 2H- 2cyt c[Fe3 + lactate for this reaction at p a. What is b. Calc H 7 and 25°C? ically, ulate the equilibrium constant for the reaction at pH 7 and 25°C. c. Calculate...
help!!
(CH3),CBr + 1 → (CH3),CI + Br the following data were collected: [(CH3)3Br] (M) Time (s) 0.600 0 0.424 10.0 0.300 20.0 0.212 30.0 0.150 40.0 Determine the rate law for this reaction and calculate the rate constant. (20 points) E (V) Thermodynamics: AGº - AH-TAS Nernst Equation: 8 = 8°-(RT/nF)InQ AGⓇ--RTINK At 25°C: 8-6° -0.0591/n)logQ AG RT K-e AG° = -nF8° Units/Constants: Volt: 1 V-1 JC Faraday: 1 F -96,485 C/mole Ea/RT Arrhenius Equation: k = Ae R-8.314...
need help with the rest of the table
EXPERIMENT 10 DETERMINATION OF THE ELECTROCHEMICAL SERIES PURPOSE To determine the standard cell potential values of several electrochemical coll INTRODUCTION The basis for an electrochemical cell is an oxidation reduction Corredor be divided into two half reactions reaction. This reaction can Oxidation half reaction Gloss of electrons) takes place at the anode, which is the positive electrode that the anions migrate to Chence the name anode) Reduction half reaction (gain of electrons)...
What results when a secondary alcohol is oxidized? a. a ketone d. an acid b. an amine e. no reaction c. an aldehyde Which of the following combinations will react spontaneously? A. 12 + Cu2+ B. Pb2+ + Ag C. Zn2+ + Mg D. Sn2+ + Ni2+ The general formula for a cycloalkane can be represented by which of the following? a. C,H, C. CH b. C.H2n+2 d. C.H21-2 In a certain reaction AH =-136 kJ and E, = 96...
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