HomeworkLib
Question

The boiling point of 200 g of H2O containing 30.0 g of a non-ionic substance is...

The boiling point of 200 g of H2O containing 30.0 g of a non-ionic substance is 101.4 degrees C. What is the molecular weight of the non-ionic substance?

Kf(water) = 1.86

Kb(water)= 0.51

science   chemistry   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

The molality of the solution is calculated, with the equation of boiling point increase:

m = ΔT / K = (101.4 - 100) / 0.51 = 2.75 m

The moles of the solute are calculated:

n = m * Kg solvent = 2.75 m * 0.2 Kg = 5.5 mol

The molar weight of the solute is calculated:

MM = g / n = 30 g / 5.5 mol = 5.45 g / mol

If you liked the answer, please rate it in a positive way, you would help me a lot, thank you.

0 0
Add a comment
Know the answer?
Add Answer to:
The boiling point of 200 g of H2O containing 30.0 g of a non-ionic substance is...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • The boiling point of 200 g of H2O containing 30.0 g of a non-ionic substance is...

    The boiling point of 200 g of H2O containing 30.0 g of a non-ionic substance is 101.4  C. What is the molecular weight of the non-ionic substance? Kf (water) = 1.86 Kb (water) = 0.51 Normal Boiling Point of water = 100.0  C Density of water = 1.0 g/mL

  • Molal Boiling-Point-Elevation and Freezing-Point-Depression Solvent Normal Boiling Point (∘C) Kb (∘C/m) Normal Freezing Point (∘C) Kf...

    Molal Boiling-Point-Elevation and Freezing-Point-Depression Solvent Normal Boiling Point (∘C) Kb (∘C/m) Normal Freezing Point (∘C) Kf (∘C/m) Water, H2O 100.0 0.51 0.0 1.86 Benzene, C6H6 80.1 2.53 5.5 5.12 Ethanol, C2H5OH 78.4 1.22 -114.6 1.99 Carbon tetrachloride, CCl4 76.8 5.02 -22.3 29.8 Chloroform, CHCl3 61.2 3.63 -63.5 4.68 Part E freezing point of 2.02 g KBr and 4.84 g glucose (C6H12O6) in 187 g of water Part F boiling point of 2.02 g KBr and 4.84 g glucose (C6H12O6) in...

  • An aqueous solution has a normal boiling point of 103 c. What is the freezing point...

    An aqueous solution has a normal boiling point of 103 c. What is the freezing point of his solution? For Water Kb= 0.51 C/m and Kf= 1.86 C/, I want the answer with datels please!!

  • a Calculate the freezing point and the boiling point of each of the following aqueous solutions....

    a Calculate the freezing point and the boiling point of each of the following aqueous solutions. (Assume complete dissociation. Assume that water freezes at 0.00°C and boils at 100.000ºC.) 0.047 m MgCl2 Kr=-1.86 °C/molal Kb =0.51 °C/molal Tf= °C Tb = °C Submit b Calculate the freezing point and the boiling point of each of the following aqueous solutions. (Assume complete dissociation. Assume that water freezes at 0.00°C and boils at 100.000°C.) 0.047 m FeCl3 Kf=-1.86 °C/molal Kb =0.51 °C/molal...

  • The boiling point of water, H2O, is 100.00°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves...

    The boiling point of water, H2O, is 100.00°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in water is sucrose. A student dissolves 10.77 grams of sucrose, C12H22O11 (342.3 g/mol), in 160.8 grams of water. Use the table of boiling and freezing point constants to answer the questions below. Solvent Formula Kb (°C/m) Kf (°C/m) Water H2O 0.512 1.86 Ethanol CH3CH2OH 1.22 1.99 Chloroform CHCl3 3.67 Benzene C6H6 2.53 5.12 Diethyl ether CH3CH2OCH2CH3 2.02 The molality of the solution is...

  • The boiling point of water, H2O, is 100.00°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves...

    The boiling point of water, H2O, is 100.00°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in water is sucrose. A student dissolves 10.90 grams of sucrose, C12H22O11 (342.3 g/mol), in 255.2 grams of water. Use the table of boiling and freezing point constants to answer the questions below. Solvent Formula Kb (°C/m) Kf (°C/m) Water H2O 0.512 1.86 Ethanol CH3CH2OH 1.22 1.99 Chloroform CHCl3 3.67 Benzene C6H6 2.53 5.12 Diethyl ether CH3CH2OCH2CH3 2.02 The molality of the solution is...

  • The boiling point of water is 100.00 °C at 1 atmosphere. A student dissolves 12.31 grams...

    The boiling point of water is 100.00 °C at 1 atmosphere. A student dissolves 12.31 grams of cobalt(II) acetate, Co(CH3COO)2 (177.0 g/mol), in 287.1 grams of water. Use the table of boiling and freezing point constants to answer the questions below. Solvent Formula Kb (°C/m) Kf (°C/m) Water H2O 0.512 1.86 Ethanol CH3CH2OH 1.22 1.99 Chloroform CHCl3 3.67 Benzene C6H6 2.53 5.12 Diethyl ether CH3CH2OCH2CH3 2.02 The molality of the solution is _____m. The boiling point of the solution is  °____C....

  • The boiling point of water, H2O, is 100.000 °C at 1 atmosphere. Kb(water) = 0.512 °C/m...

    The boiling point of water, H2O, is 100.000 °C at 1 atmosphere. Kb(water) = 0.512 °C/m In a laboratory experiment, students synthesized a new compound and found that when 13.10 grams of the compound were dissolved in 212.3 grams of water, the solution began to boil at 100.092 °C. The compound was also found to be nonvolatile and a non-electrolyte. What is the molecular weight they determined for this compound ? g/mol

  • can y’all help me please? The freezing point of water, H2O, is 0.000 °C at 1...

    can y’all help me please? The freezing point of water, H2O, is 0.000 °C at 1 atmosphere. K(water)--1.86 °C/m In a laboratory experiment, students synthesized a new compound and found that when 12.51 grams of the compound were dissolved in 213.6 grams of water, the solution began to freeze at -1.813 °C. The compound was also found to be nonvolatile and a non-electrolyte What is the molecular weight they deterfnined for this compound ? g/mol The boiling point of chloroform,...

  • Calculate the freezing point and boiling point of a solution containing 17.4 g of naphthalene (C10H8)...

    Calculate the freezing point and boiling point of a solution containing 17.4 g of naphthalene (C10H8) in 112.0 mL of benzene. Benzene has a density of 0.877 g/cm3. Part A Calculate the freezing point of a solution. (Kf(benzene)=5.12∘C/m.) Part B Calculate the boiling point of a solution. (Kb(benzene)=2.53∘C/m.)

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT