here,
mass of frozen vegetable juice , m = 0.3 kg
initial temperature , Ti = - 10 degree C
final temperature , Tf = 5 degree C
the energy required , E = m * ( Ci * ( 0 - Ti) + Lf + Cw * ( Tf - 0))
E = 0.3 * ( 2100 * 10 + 334000 + 4186 * 5) J
E = 1.13 * 10^5 J
How much energy is required to heat a 0.3kg package of frozen vegetable juice to 5...
How much heat must be removed to completely freeze 15 kg of water initially at 95°F? For water : Cice = 2100 J kg.K Cwater = 4186 kg K Lf=3 J . 34 x 10° ke, L, = 2. 26 x 100 kg
How much heat energy in joules must be added to 78 grams of water initially at 23 degrees Celsius if it ends up at 53 degrees Celsius. Remember that the specific heat capacity of water = 4186 J/ (kg oC) or 1 calorie / (g oC)
How much heat is required to convert solid ice with a mass of 850 g and at a temperature of -26.5 °C to liquid water at a temperature of 64.5 °C? (The specific heat of ice is cice = 2100 J/kgK, the specific heat of water is cwater = 4186.8 J/kgK, and the heat of fusion for water is: Lf = 334 kJ/kg.)
How much heat is required to convert solid ice with a mass of 585 g and at a temperature of -29.0 °C to liquid water at a temperature of 74.5 °C? (The specific heat of ice is cice = 2100 J/kgK, the specific heat of water is cwater = 4186.8 J/kgK, and the heat of fusion for water is: Lf = 334 kJ/kg.)
How much heat is required to convert solid ice with a mass of 545 g at a temperature of -30.0 °C to liquid water at a temperature of 58.5 °C? The specific heat of ice is cice = 2100 J/kgK, the specific heat of water is cwater = 4186.8 J/kgK, and the heat of fusion for water is Lf = 334 kJ/kg.
How much heat is required to convert solid ice with a mass of 805 g at a temperature of -24.5 °C to liquid water at a temperature of 86.5 °C? The specific heat of ice is cice = 2100 J/kgK, the specific heat of water is cwater = 4186.8 J/kgK, and the heat of fusion for water is Lf = 334 kJ/kg.
1. How much heat energy is required to change a 0.50-kg of ice at – 10 0C to steam at 110 0C? [Lf = 3.33 x 105 J/kg, c ice = 2090, c water = 4186 J/kg.0C, Lv = 2.26 x 106 J/kg, c steam = 2010 J/kg.0C]
How much heat is required to convert solid ice with a mass of 525 g and at a temperature of-23.5 °C to liquid water at a temperature of 48.5 °C? (The specific heat of ice is cice = 2100 /kgK, the specific heat of water is cwater-4186.8 J/kgK, and the heat of fusion for water is: Lf 334 kJ/kg.) Submit Answer Tries 0/12
How much energy is required to turn 5.00 kg of ice at -25.0 degrees C to steam at 140 degrees C? Show your work. cice = 2090 J/kg•oC Lfusion (water) = 3.33 x 105 J/kg cwater = 4186 J/kg•oC Lvapor(water) = 2.26 x 106 J/kg csteam = 2010 J/kg•oC
How much energy is required to turn 5.00 kg of ice at -25.0 degrees C to steam at 140 degrees C? Show your work. cice= 2090 J/kg•oC Lfusion (water)= 3.33 x 105J/kg cwater= 4186 J/kg•oC Lvapor(water)= 2.26 x 106J/kg csteam= 2010 J/kg•oC