In a similar experiment, the combination of 11.622g of Lauric acid and 2.252g of an unknown acid caused the new freezing point of Lauric acid solution to be 37.0 ºC. Use this data to calculate the molar mass of the unknown acid. For the credit show, all calculations used to determine the molar mass.
In a similar experiment, the combination of 11.622g of Lauric acid and 2.252g of an unknown...
No water was added, the only substances in the flask was the
lauric acid and the unknown. we were finding the freezing point.
heated the glass to 60c everything dissolved took it out of hot
bath and recorded temp drop which stopped at 39.44c
Unknown # Identify the unknown: Data: nknen Mass of Lauric Acid 9427 kat Et 31.442 43,2 Freezing Point of Lauric Acid Mass of Unknown .922 Freezing Point of Mixture Results and Discussion: (SHOW WORK FOR CREDIT)...
REPORT SHEET EXPERIMENT Freezing Point 19 Depression A. Preparation of experimental apparatus and acid aPreparation of experimental apparatus and freezing point determinati freezing point determination of laurie I. Mass of freezing point depression apparatus 2. Mass of freezing point depression apparatus with lauric acid 8n 519 ang 3. Mass of laurie acid used mass acid ana nd arpo B. Freezing point determination of a laurie acid solution 4. Designation of unknown 5. Mass of added unknown, Exp. 3 6. Mass...
Mass of lauric acid= 8.0021g Mass of unknown solute= 1.0036g Freexing temperature of pur lauric acid=42.62 Freezing temperature point of the unknown solute and lauric acid =36.09 Calculate mole of benzoic acid solute, using the molality and the mass of lauric acid solvent Calculate the experimental molar mass of benzoic acid , in g/mol
The freezing point of pure lauric acid was measured. Then the freezing point of a solution of 4.003 g of lauric acid with 0.399g of unknown was measured. Determine the molar mass of the unknown. Kf for lauric acid = 4.4 °C/m. Freezing point of Lauric acid =44°C Freezing point of Unknown= 39°C
Find the freezing point depression of pure lauric acid-unknown solution. Find the molality of the unknown. Info: Kf= 4.40*C/moles solute Freezing point of pure lauric acid- 43.2*C and freezing point of solution- 42 *C Mass of unknown solid (nonelectrolyte)- 0.0612g, mass of lauric acid- 3.9321g
DATA AND CALCULATIONS Mass of lauric acid Mass of benzoic acid Freezing temperature of pure lauric acid Freezing point of the benzoic acid-lauric acid mixture Freezing temperature depression, At 38-1c Molality, m molkg Moles of benzoic acid mol Molecular weight of benzoic acid (experimental) g/mo Molecular weight of benzoic acid (accepted) g/mol Percent error
A TARLES ca Part I: Benzoic acid and laurie Acid Mass of uric acid grams) Mass of benzoic acid grams) Freezing temperature of pure lauric acid (°C) From Part 8.02 11.04 g. 4 2.95 4 227900 Freezing point of the benzoic acid and lauricucid ("C) Part III: Unknown solute and lauric Acid Mass of lauric acid (grams) 8.0 49 Mass of unknown solute (grams) P.98g Freezing temperature of pure lauric acid ("C) (From Part 45°C Freezing point of the unknown...
9. A solution of 1,035 g of benzoic acid in 8.525 g of lauric acid had a freezing point of 39.6 C What is the molar mass of benzoic acid? The freezing point of lauric acid is 43.2 C and Kris 3.60 C.kg/mol.
Hi, I need some help with Chemistry.
Q1:
Q2:
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You add 0.0336 moles of benzoic acid solute to 16.00 g of an unknown solvent, which lowers the freezing point of the solvent by 8.6 °C. Calculate the freezing point depression constant (Kf) of the unknown solvent. You dissolve 1.00 g sample of an unknown solute is in 8.00 g of lauric acid, which lowers the freezing point by 5.0...
how do i find delta T of benzoic acid? as well as delta T of
unknown and the experimental molar mass of unknown??
also what would the equation be?
Pure solvent Mass of Lauric acid TFP (pure solvent) (Trial 1) (Typ freezing point temperature from graph) 8.03g 1200 42.00 42.00 42.6°C TFP (pure solvent) (Trial 2) Average TFP (pure solvent) Unknown code Benzoic acid (2 pts.) Mass of benzoic acid TFP (solution) (Trial 1) TFP (solution) (Trial 2) 1.05g (2...