In a simple random sample of 1100 young people, 87% had earned a high school diploma....
In a simple random sample of 1100 young people, 87% had earned a high school diploma. Complete parts a through below:
a. What is the standard error for this estimate of the percentage of all young people who earned a high school diploma? Answer ______ (Round to four decimal places as needed.)
b. Find the margin of error, using a 95% confidence level, for estimating the percentage of all young people who earned a high school diploma. (Answer)______% (Round to one decimal place as needed.)
c. Report the 95% confidence interval for the percentage of all young people who earned a high school diploma.Answer (___% , _____%) (Round to one decimal place as needed.)
Homework Answers
soution:-
given that p = 0.87 , n = 1100
a. standard error = sqrt(p*(1-p)/n)
= sqrt(0.87*(1-0.87)/1100)
= 0.0101
b. the value of 95% confidence from z table is 1.96
margin of error formula
=> z * standard error
=> 1.96 * 0.0101
=> 0.02
=> 2.0 %
c. confidence interval formula
=> p +/- margin of error
= 0.87 +/- 0.02
= (0.85 , 0.89)
= (85.0% , 89.0%) rounded
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In a simple random sample of 1100 young people, 87% had earned
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