Question

4) In universe MdUP, the periodic table differs as the rules for the quantum numbers differ from our universe. In MdUP, the rules for the quantum numbers are: i) The principle quantum number (n) must be a positive integer like our universe. ii) The angular momentum quantum number (l) is also the same (l= 0, …, n-1). The numbers also correspond to the same orbital shapes (s, p, d, f) that they do in our universe. iii) The magnetic quantum number (ml) differs in MdUp. Only 0 and positive integers are possible (ml = 0, ..., l). iv) The spin quantum number (ms) can be -1, 0, or +1. Like in our universe, in MdUP no electron in an atom can have the same exact four quantum numbers (n, l, ml, ms). The relative energy levels of the orbitals are the same as in our universe (e.g., 2s is higher in energy than 1s but 2s is lower than 2p). Sketch what the periodic table would look like in the MdUP universe for elements 1-10 (H through Ne). For each element write the valence shell electron configuration

Answer 1

The given rules are

1. n= 1,2,3,.....

2. l= 0,1,2,3....n-1

3. m_l = 0,1,2.....l

4. m_s = -1 , 0 , +1

5. Energy order is 1s<2s<2p

In MdUP universe the perodic table would look as follows

s-Block elements: H,He, Be,B, C,

Inert gas : Li

p-Block elements: N, O, F, Ne

valence Shell electronic configuration is as follows

1. H : 1s¹ (n=1,l=0, m_l = 0, m_s = -1)

2. He : 1s² (n=1,l=0, m_l = 0, m_s =0)

3. Li : 1s³ (n=1,l=0, m_l = 0, m_s = +1)

4. Be : [Li] 2s¹ (n=2,l=0, m_l = 0, m_s = -1 )

5. B : [Li] 2s² (n=2,l=0, m_l = 0, m_s = 0 )

6. C : [Li] 2s³ (n=2,l=0, m_l = 0, m_s = +1)

7. N : [Li] 2s³ 2p¹    (n=2,l=1, m_l = 0, m_s = -1 )

8. O : [Li] 2s³ 2p² (n=2,l=1, m_l = 0, m_s = 0 )

9. F : : [Li] 2s³ 2p³ (n=2,l=1, m_l = 0, m_s = +1)

10. Ne : [Li] 2s³ 2p⁴ (n=2,l=1, m_l = 1, m_s = -1)

The quantum number showed beside Electronic configuration is of the valence electron that is newly added.

Hund's rule, Pauli's exclusion principle are also followed for writing the above configuration.

Hope all is clear.

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