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The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean...

The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.976 grams and a standard deviation of 0.281 grams. Find the probability of randomly selecting a cigarette with 0.723 grams of nicotine or less. Then Round your answer to four decimals to find answer.

P(X<0.723)=

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Answer #1

Ans:

Given that

mean=0.976

standard deviation=0.281

z=(0.723-0.976)/0.281

z=-0.900

P(z<-0.900)=0.1840

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