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A sample of water is found to contain 0.027 ppm of Pb^2+ ions. calculate the mass...

A sample of water is found to contain 0.027 ppm of Pb^2+ ions. calculate the mass of lead ions per liter of this solution ( assume the density of the water solution solution is 1.0g/mL)
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Answer #1

1 ppm= 1 mg Pb2+ in 1 liter
= 0.001 g per liter
0.027 ppm Pb2+ ions in water = 0.027 ppm x 0.001 g/l
= 0.027 x10^-3 g/l
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