If 11.5 g of CCl3F is enclosed in a 1.2 L container, calculate the number of moles of CCl3F in the gas phase. Express your answer using two significant figures.
Ans :
pressure = 856 torr
Volume = 1.2 L
Using the ideal gas law , pV = nRT
where R = 62.36367 L.torr/K.mol
Temperature = 300 K
putting all the values :
856 x 1.2 = n x 62.36367 x 300
n = 0.055 mol
So the mol of CCl3F is gas phase will be 0.055 mol
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