What mass of NaCl is used to make 100.0 mL of a 0.0800 M NaCl solution?
We know that
Molariy= moles of NaCl/volume of solution in L
moles of NaCl = molarity*volume of solution in L = 0.0800*0.1= 8*10^-3 moles
mass of NaCl = moles*molar mass= 8*10^-3*58.44=0.467 gram NaCl
What mass of NaCl is used to make 100.0 mL of a 0.0800 M NaCl solution?
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