HomeworkLib
Question

A new metal alloy is found to have a specific heat capacity of 0.570 J/(g⋅∘C). First,...

A new metal alloy is found to have a specific heat capacity of 0.570 J/(g⋅∘C). First, 42.5 g of the new alloy is heated to 200. ∘C. Then, it is placed in an ideal constant-pressure calorimeter containing 65.0 g of water (Cs,water=4.184 J/(g⋅∘C)) at an initial temperature of 20.0 ∘C. What will the final temperature of the mixture be after it attains thermal equilibrium?

science   chemistry   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

0 0
Add a comment
Know the answer?
Add Answer to:
A new metal alloy is found to have a specific heat capacity of 0.570 J/(g⋅∘C). First,...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • 2. (15 pts) A 83.5 g sample of a metal alloy is heated to 88.1°C and...

    2. (15 pts) A 83.5 g sample of a metal alloy is heated to 88.1°C and it is then placed in a coffee-cup calorimeter containing 30.0 g water at 15.0°C. The final temperature of the metal + water is 25.3 °C. Calculate the specific heat of metal alloy, in J/(g°C), assuming no heat escapes to the surroundings or is transferred to the calorimeter. The specific heat of water is 4.184 J/(g°C).

  • A 83.5 g sample of a metal alloy is heated to 88.1oC and it is then...

    A 83.5 g sample of a metal alloy is heated to 88.1oC and it is then placed in a coffee-cup calorimeter containing 30.0 g water at 15.0oC. The final temperature of the metal + water is 25.3 oC. Calculate the specific heat of metal alloy, in J/(g oC), assuming no heat escapes to the surroundings or is transferred to the calorimeter. The specific heat of water is 4.184 J/(g oC).

  • Calculating specific heat capacity A constant-pressure calorimeter is often used to find the specific heat capacity...

    Calculating specific heat capacity A constant-pressure calorimeter is often used to find the specific heat capacity of a substance if it is not known. A known mass of the substance can be heated and added to water of known mass and initial temperature. Since the specific heat capacity of water is known ( C s,water =4.184J/(g⋅ ∘ C)) , the amount of heat transferred to the water can be calculated by measuring the final temperature of the mixture at thermal...

  • UL. HAL IVCI U IS DIUROFIN S 2. (15 pts) A 83.5 g sample of a metal alloy is heated to 88.1°C and it is then placed...

    UL. HAL IVCI U IS DIUROFIN S 2. (15 pts) A 83.5 g sample of a metal alloy is heated to 88.1°C and it is then placed in a coffee-cup calorimeter containing 30.0 g water at 15.0°C. The final temperature of the metal + water is 25.3 "C. Calculate the specific heat of metal alloy, in J/g °C), assuming no heat escapes to the surroundings or is transferred to the calorimeter. The specific heat of water is 4.184 J/g °C)....

  • Specific Heat Capacity A 21.5-g sample of an unknown metal is heated to 94.0°C and is...

    Specific Heat Capacity A 21.5-g sample of an unknown metal is heated to 94.0°C and is placed in a insulated container containing 128 g of water at a temperature of 21.4°C. After the metal cools, the final temperature of the metal and water is 25.0°C. Calculate the specific heat capacity of the metal, assuming that no heat escapes to the surroundings. Heat loss=Heat gained. Specific Heat Capacity of water is 4.18 J/g/K in this temperature range. Submit Answer Incompatible units....

  • (8 pts) An alloy with a specific heat capacity of 0.50 J/gk is heated to 555°C...

    (8 pts) An alloy with a specific heat capacity of 0.50 J/gk is heated to 555°C and immersed into 65.00 g of cool water with a temperature of 20.0℃、627 g of water evaporate. what is the mass of the alloy? 5.

  • A mass of 45.0 gg of an unknown solid initially at 160.0 ∘C∘C is added to...

    A mass of 45.0 gg of an unknown solid initially at 160.0 ∘C∘C is added to an ideal constant-pressure calorimeter containing 100.0 gg of water (Cs,water=4.184 J/(g⋅∘C))(Cs,water=4.184 J/(g⋅∘C)) initially at 20.0 ∘C∘C. After the mixture reaches thermal equilibrium, the final temperature is recorded to be 38.60 ∘C∘C. What is the specific heat capacity of the unknown solid? Express your answer to three significant figures.

  • A 60.80 gram sample of iron (with a heat capacity of 0.450 J/g◦C) is heated to...

    A 60.80 gram sample of iron (with a heat capacity of 0.450 J/g◦C) is heated to 100.00 ◦ It is then transferred to a coffee cup calorimeter containing 52.42 g of water (specific heat of 4.184 J/ g◦C) initially at 20.47 ◦C. If the final temperature of the system is 28.78, what was the heat gained by the calorimeter? If the calorimeter had a mass of 25.19 g, what is the heat capacity of the calorimeter?

  • . A 150.0 g sample of a Metal was heated to 95.0°C. When the hot metal...

    . A 150.0 g sample of a Metal was heated to 95.0°C. When the hot metal was placed into 100.0 g of water in a calorimeter, the temperature of the water increased from 20.0°C to 35.0°C. The specific heat of water is 4.184 J/g °C. a) What is the specific heat of the metal? Kb) What would the final temperature be if the mass of water was 150.0 q?

  • A piece of metal with a specific heat of 1.29 J/g°C is heated to 126.6°C and...

    A piece of metal with a specific heat of 1.29 J/g°C is heated to 126.6°C and then placed in 133.868 g of water which is at a temperature of 10.9 °C. After a minute, the temperature of the water has stopped changing and is now 45.6°C. Assuming that there are no heat losses to the container or surroundings, what is the mass of the piece of metal in grams? Assume that water has a specific heat of 4.184 J/g°C. Enter...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT