A highway guardrail is designed so that it can be distorted as much as 5cm when struck by a car. What is the minimum spring constant of the guardrail if it is to withstand the impact of a car with 1.09X10^4 J of energy?
Energy of the car = E = 1.09 x 104 J
Maximum distortion of the guardrail = X = 5 cm = 0.05 m
Spring constant of the guardrail = k
For minimum spring constant the distortion will be maximum.
The energy of the car is converted into the potential energy of the guardrail as the car comes to a stop.
E = kX2/2
1.09x104 = k(0.05)2/2
k = 8.72 x 106 N/m
Minimum spring constant of the guardrail to withstand the impact of the car = 8.72 x 106 N/m
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