Question

George and Edward are manning a cannon that sits fifty feet above the water in a...

George and Edward are manning a cannon that sits fifty feet above the water in a fortress tower. They load, aim , and fire their cannon. The cannon ball has an initial vertical velocity of 72 feet per second and hits the pirate ship ten feet above the water line exactly 5.0 seconds later. They fire a second shot, the cannonball reaches its target after only 3.5 seconds. WHAT WAS THE INITIAL VERTICAL VELOCITY OF THEIR SECOND CANNONBALL IN FEET PER SECOND. must show equation and work.

Thanks

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
George and Edward are manning a cannon that sits fifty feet above the water in a...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • (1 point) A student with a third floor dormitory window 32 feet off the ground tosses a water bal...

    A student with a third floor dormitory window 32 feet off the ground tosses a water balloon straight up in the air with an initial velocity of 16 feet per second. It turns out that the instantaneous velocity of the water balloon is given by the velocity function v(t) = -32t + 16, where v is measured in feet per second and t is measured in seconds. Let s(t) represent the height of the water balloon above the ground at time...

  • A student throws a water balloon with speed vo from a height h = 1.52 m at an angle θ=39° above the horizontal toward a target on the ground.

    A student throws a water balloon with speed vo from a height h = 1.52 m at an angle θ=39° above the horizontal toward a target on the ground. The target is located a horizontal distance d = 7.5 m from the student's feet. Assume that the balloon moves without air resistance. Use a Cartesian coordinate system with the origin at the balloon's initial position. Part (a) what is the position vector, Rtarget that originates from the balloon's original position and...

  • Homework-2 – Working with a class. Problem: Attached with this homework is code for a class...

    Homework-2 – Working with a class. Problem: Attached with this homework is code for a class called DroppedObject. This class is used to to store the state of a falling object. The problem this class/object can be used to solve is detailed below. Your task for this homework is to read and understand the attached class. Note this class is formatted like all classes should be with private variables, constructors, a toString method, getter and setter methods, and other relevant...

  • Please, I need help answering questions 10, 11, 12, 13, 14, and 15. Use the other...

    Please, I need help answering questions 10, 11, 12, 13, 14, and 15. Use the other pages as information to solve the questions. Use the questions below to keep track of key concepts from this lesson's study activity. YOUR ASSIGNMENT: Splatapults Away! The engineering club has built a catapult and wants to test it out. The local supermarket has donated some overripe fruits and vegetables, and now the club is holding a Splatapult challenge to see who can hit the...

  • HW#5 Functions and Arrays For HW#5 we will return to the state method of solving the...

    HW#5 Functions and Arrays For HW#5 we will return to the state method of solving the ballistic projectile problem with added twists. The goal will be to hit a target 1000 meters east of your cannon but the wind is blowing from the south. Your initial muzzle velocity is fixed at 110 meters per second, but you can control the elevation and azimuth angles of your aim. Elevation angle is measured up or down. Azimuth angle is measured right or...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT