How many moles of camphor could be theoretically reduced by the amount of NaBH4 used (.0150 mol used), given that NaBH4 can technically reduce four molecules of ketone? The amount of camphor that was used was 1.27 g (.00834 mol). Please show how you got it.
Camphor have 1 ketone (-C=O) bond in it , so we can say 1 camphor = 1 ketone molecule .
As 1 mole of NaBH4 reduces = 4 ketone moles
Them 0.0150 mol used should reduce = 0.0150×4 = 0.06 mol of ketone .
And thus theoretically , 0.06 moles of Camphor should be reduced by the used (0.0150 moles) of NaBH4 .
How many moles of camphor could be theoretically reduced by the amount of NaBH4 used (.0150...
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