A 75 kg hiker has fallen down a hole. One rescuer attaches a rope to the...
A 75 kg hiker has fallen down a hole. One rescuer attaches a rope to the injured hiker and then a second rescuer pulls the injured hiker straight up out of the hole at a steady rate. How much force would the second rescuer need to exert on the rope to do this?
Homework Answers
Since, the injured hiker is being pulled at constant rate, net acceleration is zero.
Using Newton's second law,
F-mg=0
F=mg
F=75*9.8 =735 N
Force applied =735 N
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