Why would a DFT (Discrete Fourier Transform) indicate that a 1Hz square wave has additional higher...
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Why would a DFT (Discrete Fourier Transform) indicate that a 1Hz square wave has additional higher frequency signals? Hint: DFTs decompose signals into what? The rapid changes at a square wave’s corners relate to frequency how?
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How does a reconstructed square wave differ from the original? Why does it look like that?
Homework Answers
Though signal system can be understood by crude mathematics and fourier series it is very important to first understand the question intuitively.
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Why would a DFT (Discrete Fourier Transform) indicate
that a 1Hz square wave has additional higher...
Question 1 --/5 ) In synthesising a square wave using Fourier synthesis with four frequencies, why...
Question 1 --/5 ) In synthesising a square wave using Fourier synthesis with four frequencies, why would we be unable to obtain a perfect square wave? (1) because the synthesis was performed in the time domain (2) because it is not possible to add sinusoidal signals (3) because amplitude errors in the signal generator would make the peaks rounded rather than flat because four frequencies are not enough Question 2 (-15) A discrete-time signal is x[n] =1.3nu[n], defined for all...
Question 1 --/5 ) In synthesising a square wave using Fourier synthesis with four frequencies, why would we be unable to obtain a perfect square wave? (1) because the synthesis was performed in the time domain (2) because it is not possible to add sinusoidal signals (3) because amplitude errors in the signal generator would make the peaks rounded rather than flat because four frequencies are not enough Question 2 (-15) A discrete-time signal is x[n] =1.3nu[n], defined for all...
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