What is the pressure of the gas (in atm) when 5.0 moles of CO gas are present in a container of 20.0 L at 27 oC?
A) 3.25 B) 6.15 C) 7.40 D) 9.30 E) 10.55
Please show how you solved.
According to ideal gas law
PV=nRT
P is the pressure
V is the volume
n is number of moles
R is universal gas constant
T is the temperature in kelvin
n= 5 moles
V=20 L
T=27+273 = 300 K
P=(nRT) /V
P=(5*0.0821 L atm mol-1 K-1*300K) /20 L
P=6.15 atm
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