Question

According to the Nielsen Company, Americans spend $345 million on chocolate during the week of Valentine’s...

According to the Nielsen Company, Americans spend $345 million on chocolate during the week of Valentine’s Day. Let’s assume that we know the average married person spends $45, with a population standard deviation of $16. In February 2009, the U.S. economy was in the throes of a recession. Comparing data for Valentine’s Day spending in 2009 with what is generally expected might give us some indication of the attitudes during the recession.

a. Compute the 95% confidence interval for a sample of 18 married people who spent an average of $38.

b. How does the 95% confidence interval change if the sample mean is based on 180 people?

c. If you were testing a hypothesis that things had changed under the financial circumstances of 2009 as compared to previous years, what conclusion would you draw in part (a) versus part (b)?

d. Compute the effect size based on these data and describe the size of the effect.

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
According to the Nielsen Company, Americans spend $345 million on chocolate during the week of Valentine’s...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • According to a 2011 report by the United States Department of Labor, civilian Americans spend 2.75...

    According to a 2011 report by the United States Department of Labor, civilian Americans spend 2.75 hours per day watching television. A faculty researcher, Dr. Sameer, at California Polytechnic State University (Cal Poly) conducts a study to see whether a different average applies to Cal Poly students. Suppose that for a random sample of 100 Cal Poly students, the mean and standard deviation of hours per day spent watching TV turns out to be 3.01 and 1.97 hours, respectively. The...

  • A nutritionis wants to determine how much time onally people spend eating and drinking Suppose for...

    A nutritionis wants to determine how much time onally people spend eating and drinking Suppose for a random sample of 913 people age 15 or older the mean amount of time spent eating or drinking per day is 174 hours wit a standard deviation of 65 hour Complete parts (al through (d) below. (a) A histogram of time sport eating and drinking each day is skewed Use this result to explain why a large sample size is needed to construct...

  • A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for...

    A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 982982 people age 15 or​ older, the mean amount of time spent eating or drinking per day is 1.181.18 hours with a standard deviation of 0.550.55 hour. Complete parts ​(a) through ​(d) below. ​(a) A histogram of time spent eating and drinking each day is skewed right. Use this result to explain why a large sample size is needed to...

  • RIGHT CLICK ON THE IMAGE AND SELECT "OPEN IMAGE IN A NEW TAB" FOR A LARGER...

    RIGHT CLICK ON THE IMAGE AND SELECT "OPEN IMAGE IN A NEW TAB" FOR A LARGER CLEARER IMAGE. A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 1048 people age 15 or older, the mean amount of time spent eating or drinking per day is 1.29 hours with a standard deviation of 0.54 hour. Complete parts (a) through (d) below. (a) A histogram of time spent eating and drinking...

  • Please use MATLAB. Part B (Based off week 11 workshop content) An engineering company has ordered steel to be used for...

    Please use MATLAB. Part B (Based off week 11 workshop content) An engineering company has ordered steel to be used for a rail construction project. Before using the steel, they want to test it to ensure the material properties from the supplier are correct A random sample of the ordered steel is tested for its Yield Strength. The results are shown below. Yield Strength (MPa) 197203194196196197198205 1. Calculate the sample mean and sample variance by hand, then verify your answers...

  • z-Tests According to the CDC the average height of 15-year-old boys is 67 inches, with a...

    z-Tests According to the CDC the average height of 15-year-old boys is 67 inches, with a standard deviation of 3.19 inches. A high school teacher believes the male students in his classes are especially tall this year. The teacher averages the heights of a random sample of the male students in his classes throughout the day (N 57) and find an average of 68.1 inches. 1. Use a two-tailed hypothesis (z) test with alpha0.01 to determine if there is any...

  • all answers please!! 1. A company that produces brendis concerned about the distribution of the amount of sodiu...

    all answers please!! 1. A company that produces brendis concerned about the distribution of the amount of sodium in its bread. The company takes a simple random sample of 100 slices of bread and compute the sample mean to be 103 milligrams of sodium per slice. Assume that the population standard deviation is 10 milligrams a) Construct a 95% confidence interval estimate for the mean sedium level. b) Construct a 99% confidence intervalestime for the mean sodium level. 2. Fill...

  • Part B (Based off week 11 workshop content) An engineering company has ordered steel to be used for a rail construction project. Before using the steel, they want to test it to ensure the material pro...

    Part B (Based off week 11 workshop content) An engineering company has ordered steel to be used for a rail construction project. Before using the steel, they want to test it to ensure the material properties from the supplier are correct. A random sample of the ordered steel is tested for its Yield Strength. The results are shown below. Yield Strength (MPa) 197 203 194 196 196 197 198 205 1. Calculate the sample mean and sample variance by hand,...

  • A research team is interested in the effectiveness of hypnosis in reducing pain. The responses from...

    A research team is interested in the effectiveness of hypnosis in reducing pain. The responses from 8 randomly selected patients before and after hypnosis are recorded in the table below (higher values indicate more pain). Construct a 90% confidence interval for the true mean difference in pain after hypnosis. Perceived pain levels 'Pre' and 'Post' hypnosis for 8 subjects Pre 11.3 8.1 8.4 11.1 13.4 15.1 10.6 10.1 Post 9.9 9.1 3.1 8.5 7.0 9.9 10.9 7.7 Difference a) Fill...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT