A 0.50-μF and a 1.4-μF capacitor (C1 and C2, respectively) are connected in series to a 22-V battery
Part B Calculate the charge on each capasitor. Express your answers using two significant figures separated by a comma and in the unit C
Part C Calculate the potential difference across each capacitor assuming the two capacitors are in parallel. Express your answers using two significant figures separated by a comma
Part D Calculate the charge on each capasitor assuming the two capacitors are in parallel. Express your answers using two significant figures separated by a comma.
b) for C2
V1 = V C2 / ( C1 + C2) = 22 * 1.4 / ( 1.4 + 0.5) = 16.21 V
q1 = C1V1 = 8.1 uC
since both are in series so they share same value of charge
q2 = q1 = 8.1 uC
======
c)
since both are in parallel so they must have same potential.
V1 = V2 = 22 V
======
d)
q1 = C1 V1 = 0.5* 22 = 11 uF
q2 = C2 V2 = 1.4* 22 = 30.8 uF
======
Comment in case any doubt, will reply for sure.. Goodluck
A 0.50-μF and a 1.4-μF capacitor (C1 and C2, respectively) are connected in series to a...
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Capacitors C1=10F
and C2=25F
are each charged to 25V , then disconnected from the battery
without changing the charge on the capacitor plates. The two
capacitors are then connected in parallel, with the positive plate
of C1 connected to the negative plate of C2 and vice versa.
Part A
Afterward, what is the charge on each capacitor?
Express your answer using two significant figures. Enter your
answers numerically separated by a comma.
Part B
What is the potential difference across...
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Two capacitors, C1 = 4.92 μF and
C2 = 14.1 μF, are connected in
parallel, and the resulting combination is connected to a 9.00-V
battery.
(a) Find the equivalent capacitance of the combination.
(b) Find the potential difference across each capacitor.
(c) Find the charge stored on each capacitor.
*PLEASE ANSWER ALL PARTS TO A, B, AND C CLEARLY* THANK YOU FOR
YOUR HELP IN ADVANCE!
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