Question

Write in C++. Write a program that takes in an integer in the range 20-98 as input. The output is a countdown starting from the integer and stopping when both output digits are identical.

Ex: If the input is:

93

the output is:

93 92 91 90 89 88

Ex: If the input is:

77

the output is:

77

Ex: If the input is:

15

or any value not between 20 and 98 (inclusive), the output is:

Input must be 20-98

For coding simplicity, follow each output number by a space, even the last one.

Use a while loop. Compare the digits; do not write a large if-else for all possible same-digit numbers (11, 22, 33, …, 88), as that approach would be cumbersome for larger ranges.

#include <iostream>
using namespace std;

int main() {

/* Type your code here. */

return 0;
}

Answer 1

#include <iostream>
using namespace std;

int main()
{
    int n;
   
    cin>>n;
    
    if(n>=20 && n<=98){
          while(!(n%10==n/10)){
             cout<<n<<" ";
             n--;
      }
      cout<<n<<endl;
   }
   else{
          cout<<"Input must be 20-98\n";
   }
   return 0;
}