How many observations should be made if the analyst wants to be 96.84 percent confident that the maximum error in the observed time is two seconds? Assume that the standard deviation of each task time is 4 seconds.
Solution
standard deviation =s =
=4
Margin of error = E = 2
At 96.84% confidence level the z is ,
Z
/2
=2.149
sample size = n = [Z
/2*
/ E] 2
n = ( 2.149*4 / 2 )2
n =18.47=18 rounded
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