A car enters a curve in the road with a speed of 44 m/sm/s and emerges...
A car enters a curve in the road with a speed of 44 m/sm/s and
emerges from this curve 16 s later with the same speed. However,
the direction of the velocity changes by 115 degrees during this
time.
What is the magnitude of the average acceleration during this time
interval?
Homework Answers
magnitude of average aceleration,
a_avg = |vf - vi|/t
|vf - vi| = sqrt(vf^2 + vi^2 - 2*vf*vi*cos(theta))
= sqrt(44^2 + 44^2 - 2*44*44*cos(115))
= 74.22 m/s
a_avg = 74.22/16
= 4.64 m/s^2 <<<<<<<<<<<---------------------Answer
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