A cemented carbide tool is used to turn a part with a
length of 14.0 in and diameter = 4.5 in. The parameters in the
Taylor equation are: n = 0.21 and C = 1100 (ft/min). The rate for
the operator and machine tool = $45.00/hr, and the tooling cost per
cutting edge = $2.10. It takes 2.5 min to load and unload
the workpart and 1.50 min to change tools. The feed =
0.015 in/rev. Determine:
(a) cutting speed for maximum production rate in
ft/min
686.59,729.48,764.85,808.34,855.42,906.77,658.75,724.42,769.48,818.39,835.21,926.66
(b) tool life of cutting in
min
6.39, 7.32,
8.50,4.50,5.02,5.64,6.39,7.32,8.50,4.50,5.02,5.64
(c) cycle time in min
4.44,
4.17,4.42,3.97,5.57,4.71,3.54,3.54,3.84,4.54,3.66,3.84
(d) cost per unit of product in $
3.01,
3.33,4.16,3.24,3.94,4.15,3.60,3.46,3.75,2.97,4.03,3.70
A cemented carbide tool is used to turn a part with a length of 14.0 in...
Question 3 Suppose a cemented carbide tool with a brazed insert is used to turn a steel workpart that is 375 mmlong and 62.5 mnm in diameter. The parameters in the Taylor equation are: n = 0.25 and C = 300 (m/min) for a feed of 0.30 mm/rev. The price of the brazed insert N$30.00, and it can be used a total of 15 times before it must be scrapped. The tool change time for the regrindable tooling 3.0 min....
Please solve 23.15 thank you!
3.14 (SI units) Solve the previous problem except that in partToo ting (a), determine the cutting speed for minimum cost. 23.15 (uSCS units) Cemented carbide inserts are used to turn 21.0 in and diameter = 4.0 in. Feed the a part with length incre that f what produ 0.015 in/rev. The parameters in the Taylor equation are n = 0.25 and C =800 (ft/nin) The operator and machine tool rate = S45.00/hr. and the tooling...
a) A workpiece (φ-75 mm, 1 275 mm) is machined using turning at a feed rate of 0.25 mm/rev. At a cutting speed- 3.5 m/s, the turning tool is ineffective after machining 3 parts, and at a cutting speed = 2.5 m/s, the turning tool is effective for producing 20 parts. Calculate the Cutting Speed that will allow 30 parts to be machined between tool changes [20 marks] b) An aluminium alloy workpiece (tensile strength - 325 N/mm2 and yield...
Flank wear data were collected in a series of turming tests using a coated carbide tool on hardened alloy steel at a feed of 0.3 mm/rev and a depth of 3.6 mm. At a speed of 120 m/min, flank wear 0.12 mm at 1 min, 0.27 mm at 5 min, 0.5 mm at 10 min, 0.58 mm at 15 min, 0.73 at 20 min, and 0.97 mm at 25 min. At a speed of 160 m/min, flank wear 0.2 mm...
Problem 1 Consider the drilling of Feature 3 (Thru Hole) on the flashlight head (Figure 1) Assume the feed of the drilling opcration (i.e., the distance the drill penetrates per unit revolution) is,f= 0.01 inrev. " a) Calculate the material removal rate (in in3/s or mm3/s). b) Use the Taylor Tool Life equation to estimate the tool life (in minutes) for this operation. Use Table 1 to pick appropriate values of C and n (the flashlight material is aluminum and...
Question 1 A turning operation is carried out on aluminum. Based on the specific energy values in Table 20.2, determine material removal rate and cutting power in the operation under the following sets of cutting conditions: (a) Cutting speed 5.6 m/s, feed 0.25 mm/rev, and depth of cut 2.0 mm; and (b) cutting speed- 1.3 m/s, feed 0.75 mm/rev, and depth 4.0 mm. Question 2 Consider a turning operation performed on steel whose hardness 225 HB at a cutting speed...