In order to qualify for letter sorting, applicants are given a speed-reading test. The scores are normally distributed, with a mean of 70 and a standard deviation of 5. The variable is also normally distributed. If only the top 10% are selected, find the cutoff score.
Given that
mean =70
standard deviation = 5
P value = 0.10
Solution :
With p value = 0.10 the corresponding z score to right is 1.282
we know that
Z = ( X -
) /
1.282 = ( X - 70 ) / 5
X = 76.41
Answer : the cutoff score. = 76.41
Note : If we round z score to 2 decimals i.e., 1.28 we get x = 76.40
so round z score according to your answer
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