a business has average sales of $145000 with a standard deviation of $8000. For this normal distribution the probability that sales will be less than $130000 is what %
Solution :
Given that ,
mean =
= 145000
standard deviation =
= 8000
P(x < 130000) = P[(x -
) /
< (130000 - 145000) / 8000]
= P(z < -1.875)
Using z table,
=0.0304
The percentage is = 3.04%
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