Question

Please do this in Java (Java FX)

Tic-Tac-Toe game (aka X's and O's) in which the player, who is "X", plays against the application, which is "O". The game should be built using the basic window-with-canvas code used for the various tutorials and course assignments. The user plays by dragging "X" tokens onto the Tic-Tac-Toe board area after which the application will automatically play by moving an "O" onto the board area. When a game is over the app should show who won, if any. If necessary review how Tic-Tac-Toe works by searching online. Here are the detailed requirements.

public class Token {
   public void drawWith(GraphicsContext thePen){
       //empty code
   }
}

public class PlayerToken extends Token {
   public void drawWith(GraphicsContext thePen){
     //code for drawing "X" tokens
   }
}

public class OpponentToken extends Token {
   public void drawWith(GraphicsContext thePen){
     //code for drawing "O" tokens
   }
}

Answer 1

import java.util.Scanner;
  
public class TicTacToeTest{
  
public static void main(String[ ] args) {
  
TicTacToe t = new TicTacToe();
Scanner s = new Scanner(System.in);
int x=0,y=0;
do
{
System.out.println(t.player==t.X?"Player X turn":"Player O turn");
System.out.println("Enter x and y places");
x=s.nextInt();
y=s.nextInt();
  
t.putSign(x, y);
System.out.println(t.toString());
System.out.println("_____________________________");
t.displayWinner();
  
}while(t.isEmpty);
}
}
  
class TicTacToe
{
public static final int X = 1, O = -1;
public static final int EMPTY = 0;
  
public int player = X;
private int[][] board = new int[3][3];
public boolean isEmpty = false;
  
/** Puts an X or O mark at position i,j. */
public void putSign(int x, int y)
{
if(x<0 || x>2 || y<0 || y>2)
{
System.out.println("Invalid board position");
return;
}
if(board[x][y] != EMPTY)
{
System.out.println("Board position occupied");
return;
}
board[x][y] = player; // place the mark for the current player
player = -player; // switch players (uses fact that O = - X)
}
  
/** Checks whether the board configuration is a win for the given player. */
public boolean isWin(int player)
{
return ((board[0][0] + board[0][1] + board[0][2] == player*3) ||
(board[1][0] + board[1][1] + board[1][2] == player*3) ||
(board[2][0] + board[2][1] + board[2][2] == player*3) ||
(board[0][0] + board[1][0] + board[2][0] == player*3) ||
(board[0][1] + board[1][1] + board[2][1] == player*3) ||
(board[0][2] + board[1][2] + board[2][2] == player*3) ||
(board[0][0] + board[1][1] + board[2][2] == player*3) ||
(board[2][0] + board[1][1] + board[0][2] == player*3));
}
  
/**display the winning player or indicate a tie (or unfinished game).*/
public void displayWinner()
{
if(isWin(X))
{
System.out.println("\n X wins...!!");
isEmpty=false;
}
else if(isWin(O))
{
System.out.println("\n O wins...!!");
isEmpty=false;
}
else
{
if(!isEmpty)
{
System.out.println("its a tie");
}
  
}
}
  
public String toString()
{
StringBuilder s = new StringBuilder();
isEmpty = false;
for(int i=0;i<3;i++)
{
for(int j=0;j<3;j++)
{
switch(board[i][j])
{
case X:
s.append(" X ");
break;
case O:
s.append(" O ");
break;
case EMPTY:
s.append(" ");
isEmpty=true;
break;
}
if(j<2)
{
s.append("|");
}
  
}
if(i<2)
{
s.append("\n-----------\n");
}
}
return s.toString();
}
}