Is this possible? The probability that a bus will arrive late at the Civic Center is 0.35, and the probability that it will be on time or early is 0.55.
True because 0.35+0.55 <1.
True because 0.35*0.55<1.
False because 0.35+0.55 <1.
False because 0.35 < 0.55.
False because 0.35+0.55 <1.
there will be three condition for the bus
A. either late or
B.early or
C.on time,
all there three event A, B and C are mutually exclusive (or disjoint) event and sum of probability of three event will be 1.
P(A)+(B)+P(C)=1
here P(A)=0.35, P(B)+P( C)=0.55
since P(A)+P(B)+P(C)=0.9 which is not equal to 1. so this is not possible ,
therefore right choice is False because 0.35+0.55 <1.
Is this possible? The probability that a bus will arrive late at the Civic Center is...
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