What is the maximum mass of P4 that can be obtained from 56.2 g Ca3(PO4)2, 37.3...
What is the maximum mass of P4 that can be obtained from 56.2 g Ca3(PO4)2, 37.3 g SiO2 and excess carbon? The chemical equation for the reaction is given below.
2 Ca3(PO4)2(s) + 6 SiO2 + 10 C(s) ⟶ P4(g) + 6 CaSiO3(l) + 10 CO(g)
Give your answer in grams with three significant figures.
Molar masses, in g mol-1:
| Ca3(PO4)2, 310.18 | SiO2, 60.09 | P4, 123.88 |
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What is the maximum mass of P4 that can be obtained
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