A 0.11 kg bullet traveling at speed hits a 18.3 kg block of wood and stays...
A 0.11 kg bullet traveling at speed hits a 18.3 kg block of wood and stays in the wood. The block with the bullet imbedded in it moves forward with a velocity of 8.8 m/s. What was the velocity (speed) of the bullet immediately before it hit the block (in m/s)?
Homework Answers
using conservation of momentum
m1 v1 = (m1 + m2) v
0.11* v1 = (18.3 + 0.11)* 8.8
v1 = 1472.8 m/s
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