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Suppose the amount of air in a person's lungs is 2.15x10^-3 m^-3 a) Calculate the number...

Suppose the amount of air in a person's lungs is 2.15x10^-3 m^-3

a) Calculate the number of moles of air molecules in the person's lungs when the pressure there is atmospheric pressure. Note that the air is at 37.0 degrees Celsius (body temperature).

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Answer #1

By ideal gas equation,

PV = nRT where symbols have usual meanings

Putting the values in SI units,

101325*2.15e-3 = n*8.314*(273+37)

n = [101325*2.15e-3]/[8.314*(273+37)]

= 0.08452 moles answer

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